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We can set up this problem as a system of linear equations. Let's represent x as the number of CD's Michael has and y as the number of CD's John has.

From the problem, this yields 2 equations:

y = 15 + x (John has 15 more CD's than Michael) and

x + y = 55 (Together they have a total of 55 CD's)

we can rewrite the first equations as x - y = -15 and from here we can use eliminations to reduce the system to one variable

(x - y = -15) + (x + y = 55) = (2x = 40)

40/2 = 20, so Michael has 20 CD's

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