Michael has 20 CDs
john johanna Margaret Mary Helena Patrick kate Michael
8 of them.
If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.
8.10 is the cost of the tickets.
The first step in solving this problem is to build two equations. 0.25Q+0.10D=2.50 and Q+D=13 where Q=total number of quarters and D=total number of Dimes. Next we try to subtract one equation from the other to eliminate one variable. So we multiply 0.25Q+0.10D=2.50 by 4 to get 1Q+0.4D=10. Then we subtract Q+0.4D=10 from Q+D=13. This results in 0.6D=3. We divide both sides by 0.6 and end up with d=5. Therefore we have 5 dimes, which equals 50 cents. Therefore we have $2 in quarters or 8 quarters. 8 quarters is the answer.
Michael has 20 CDs
M+(m+15)=55 or Michael has 20 cards.
John Michael Montgomery is a country singer, and an American role model. He has 30 singles on the charts, and is a hit music man. John Montgomery is a true American.
We can set up this problem as a system of linear equations. Let's represent x as the number of CD's Michael has and y as the number of CD's John has. From the problem, this yields 2 equations: y = 15 + x (John has 15 more CD's than Michael) and x + y = 55 (Together they have a total of 55 CD's) we can rewrite the first equations as x - y = -15 and from here we can use eliminations to reduce the system to one variable (x - y = -15) + (x + y = 55) = (2x = 40) 40/2 = 20, so Michael has 20 CD's
John Landis
Madonna, Michael Jackson, Daryl Hall and John Oats.
Actors Entertainment - 2009 Sidebeat Music with Fancy and John Michael Ferrari 3-89 was released on: USA: 23 April 2011
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