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Michael has 20 CDs

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Q: John has 15 more music cds than Michael together they have a total of 55 cds how many cds does Michael have?
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John has a total of 13 coins in his pocket Of the 13 coins they are all either quarters or dimes The total value of the coins is 2.50 How many quarters does John have in his pocket?

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John has a total of 13 coins in his pocket Of the 13 coins they are all either quarters or dimes The total value of the coins is 250 How many dimes does John have in his pocket?

If all coins were dimes he would have $1.30. Every quarter that replaces a dime increases the total by 15c. The total has to be increased by $1.20 which is 15c x 8. He has 8 quarters and 5 dimes.


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John has a total of 13 coins in his pocket of the 13 coins thay are all either quarter or dimes the total value of the coins is 2.50 how many quarters does john have his pocket?

The first step in solving this problem is to build two equations. 0.25Q+0.10D=2.50 and Q+D=13 where Q=total number of quarters and D=total number of Dimes. Next we try to subtract one equation from the other to eliminate one variable. So we multiply 0.25Q+0.10D=2.50 by 4 to get 1Q+0.4D=10. Then we subtract Q+0.4D=10 from Q+D=13. This results in 0.6D=3. We divide both sides by 0.6 and end up with d=5. Therefore we have 5 dimes, which equals 50 cents. Therefore we have $2 in quarters or 8 quarters. 8 quarters is the answer.

Related questions

John has 15 more music CDs than Michael. Together they have a total of 55 CDs. How many CDs does Michael have?

Michael has 20 CDs


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John has 15 more music CD's than Michael together they have a total of 55 CD's how many cds does Michael have?

We can set up this problem as a system of linear equations. Let's represent x as the number of CD's Michael has and y as the number of CD's John has. From the problem, this yields 2 equations: y = 15 + x (John has 15 more CD's than Michael) and x + y = 55 (Together they have a total of 55 CD's) we can rewrite the first equations as x - y = -15 and from here we can use eliminations to reduce the system to one variable (x - y = -15) + (x + y = 55) = (2x = 40) 40/2 = 20, so Michael has 20 CD's


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