The amps you can get from a 500 kVA transformer would depend on the voltage of the transformer's output. To calculate amperage, you can use the formula: Amps = Power (kVA) / Voltage. For example, if the output voltage is 480V, you would get approximately 1041 amps (500 kVA / 480V).
To calculate the kilowatts (kW) when given voltage (V) and current (I), you can use the formula: kW = V x I x √3 / 1000 For 480V, the calculation would be based on the current flowing through the circuit.
To convert kVA to amps, you need to also know the voltage. If we assume a standard voltage of 480V, then 300 kVA would be approximately 360 amps. This is calculated by dividing the kVA by the voltage and then converting to amps using the formula: Amps = (kVA * 1000) / (1.732 * Volts) where 1.732 is the square root of 3.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
1.3 amps
Answer: To determine the amperage in a circuit. Notes: Power (in watts) = Volts * Amps 16.4 KVA = 480V * Amps 16400 / 480 = Amps ~34.2 = Amps
The amps you can get from a 500 kVA transformer would depend on the voltage of the transformer's output. To calculate amperage, you can use the formula: Amps = Power (kVA) / Voltage. For example, if the output voltage is 480V, you would get approximately 1041 amps (500 kVA / 480V).
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
At 240v single phase it's 70.8 amps. If it runs on 2 wires plus ground, take the voltage rating of the equipment and divide that into the watts to get amps. At 480v 3 phase it's 25.8 amps. At 208v 3 phase it's 47.2 amps. <<>> There are zero amps in 14 kW. A voltage needs to be stated. I = W/E, Amps = Watts/Volts.
To calculate the kilowatts (kW) when given voltage (V) and current (I), you can use the formula: kW = V x I x √3 / 1000 For 480V, the calculation would be based on the current flowing through the circuit.
100 amps to a 3 phase load. Power = 100A x Voltage x 1.73 ((line to line voltage)(1.73=SQRT(3)). 173 amps to each of 3 single phase (line to line) loads. Power = 173A x Voltage (line to line voltage). or... 100 amps to each of 3 single phase (line to neutral) load. Power = 300A x Voltage (line to neutral voltage). Example: - 3 phase, 480v, 100amp to a 3 phase heater. 100A x 480V x 1.73 = 83040 watts. - 3 single phase 480v (L-L voltage) heaters, 100amp. 173A x 480V = 83040 watts. - 3 single phase 277v (L-N voltage) heaters, 100amp. 300A x 277V = 83100 watts.
Since this transformer has a ratio of 1:2 the load current on the 480V side just has to be doubled. 85 x 2 = 170A on the primary. 40.8 KVA transformer. To prove this just find the KVA of both sides and they should be equal.
To convert kVA to amps, you need to also know the voltage. If we assume a standard voltage of 480V, then 300 kVA would be approximately 360 amps. This is calculated by dividing the kVA by the voltage and then converting to amps using the formula: Amps = (kVA * 1000) / (1.732 * Volts) where 1.732 is the square root of 3.
1kw=1.25kvaby this relation 75kva=60kwp=1.732*380*I*1I=60000/1.732*380*1I=91AmpsCommentPower factor is irrelevant to this question. You don't need to convert the kV.A rating to kilowatts, simply divide 75 000 V.A by (1.732 x 380). The answer is 114 A.This, of course, assumes that the question refers to a three-phase generator and that 380 V is the line voltage.
The formula you are looking for is; Amps = HP x 746/1.73 x Volts x %eff x pf. 350 x746/1.73 x 480 x .90 x .90 = 261100/672 = 389 amps. This amperage assumes that the efficiency of the motor is at 90% and the power factor of the motor is also at 90%.
A: My advice is do not try it 120 v will require 480v /120 or 4 times the current. assuming 100% efficiency. a transformer can do it but there will be a loss of 20% . House wiring is 15 amps per circuit . So if your whatever unit needs more the 3 amps it just cannot be done. A PWM can also do this job more efficiently but then again the total power is in question.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.