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80 ft / sec ~ 55mph

The above ignores air resistance which will not be significant at this speed.

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14y ago
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3mo ago

Assuming the acceleration due to gravity is -9.81 m/s^2, we can use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration due to gravity, and t is the time taken (2.5 seconds). Plug in the values to get v = 0 + (-9.81 × 2.5) = -24.525 m/s. The negative sign indicates the direction of the velocity, in this case, downwards.

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Q: A cliff diver plans to jump off a cliff into a river and needs to know the velocity with which she will strike the water. it takes a rock 2.5 seconds to reach the water. what'ld her final velocity be?
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Related questions

A squirrel drops a nut over a cliff what is the velocity of the nut after 3 seconds?

Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.


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According to the Laws of Physics, Horizontal Velocity is unaffected by Vertical Velocity. Thus you need to first find how long it will take the stone to hit the ground. Assume: Acceleration due to gravity = 9.8 m/s^2 Velocity due to gravity = 9.8x m/s, where x is seconds Displacement due to gravity = 9.8x^2 m, where x is seconds Set Displacement = to 78.4m 78.4m = 9.8x^2 m and solve for.. x = sqrt(8) = 2 sqrt(2) Then to find displacement horizontally, multiply time*velocity horizontally distance from base of cliff = (2 sqrt(2))s * 8 m/s = 16 sqrt(2) m


A ball is thrown horizontally from a cliff at a speed of 15 ms and strikes the ground 45 meters from the base of the cliff. How long was the ball in the air3?

The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.


A rock is thrown from a cliff and hits the ground 5 seconds later at a distance of 50 meters from the cliff How high was the cliff?

Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.


A rock is dropped from the top of a cliff what is the velocity after 2 seconds 5 seconds 10 seconds?

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A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?

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A ball is thrown horizontally at 20 m s from the top of a cliff 50 meters high How far form the base of the cliff does the ball strike the ground?

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A ball is thrown horizontally at 20 meters from the top of a cliff 50 meters high How far from the base of the cliff does the ball strike the ground?

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What does initial velocity means?

Initial velocity refers to the velocity of an object at the very beginning of its motion or in a particular interval of time. It is typically denoted as "u" in physics equations and is crucial for determining the subsequent motion and trajectory of the object. Initial velocity is an important parameter in analyzing various phenomena such as projectile motion, collisions, and more.


A ball is thrown horizontally from a cliff and hits the ground 4 seconds later 40 meters from the base of the cliff. How fast was the ball thrown?

The horizontal speed of the ball can be calculated using the equation: horizontal distance = horizontal speed * time. In this case, the horizontal distance is 40 meters and the time is 4 seconds. Therefore, the horizontal speed of the ball was 10 m/s.