80 ft / sec ~ 55mph
The above ignores air resistance which will not be significant at this speed.
Assuming the acceleration due to gravity is -9.81 m/s^2, we can use the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration due to gravity, and t is the time taken (2.5 seconds). Plug in the values to get v = 0 + (-9.81 × 2.5) = -24.525 m/s. The negative sign indicates the direction of the velocity, in this case, downwards.
The impact velocity of a rock thrown horizontally from a cliff will depend on the height of the cliff and the initial velocity at which it was thrown. If air resistance is neglected, the velocity of impact will be equal to the horizontal component of the initial velocity.
A sharp cliff caused by sudden movements along dip-slip faults is called an earthquake. It causes the ground to shake for several seconds.
The time it takes for the sound to travel to the cliff and back as an echo is 4 seconds. Since the sound wave travels twice the distance to the cliff and back, the total distance traveled is 2 × 680 = 1360 meters. Using the formula speed = distance/time, we can calculate the speed of sound. The period of the sound wave is the time it takes for one complete cycle, which in this case is the time it takes for the sound to travel to the cliff and back, which we found to be 4 seconds.
If it takes 15 seconds for an echo to be heard, the distance between you and the reflecting surface (such as a wall, cliff, or building) is approximately 2,250 meters (15 seconds multiplied by the speed of sound at sea level, which is about 343 meters per second).
The hiker stood on the cliff, admiring the breathtaking view below.
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
According to the Laws of Physics, Horizontal Velocity is unaffected by Vertical Velocity. Thus you need to first find how long it will take the stone to hit the ground. Assume: Acceleration due to gravity = 9.8 m/s^2 Velocity due to gravity = 9.8x m/s, where x is seconds Displacement due to gravity = 9.8x^2 m, where x is seconds Set Displacement = to 78.4m 78.4m = 9.8x^2 m and solve for.. x = sqrt(8) = 2 sqrt(2) Then to find displacement horizontally, multiply time*velocity horizontally distance from base of cliff = (2 sqrt(2))s * 8 m/s = 16 sqrt(2) m
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
The velocity after 2 seconds, 5 seconds, and 10 seconds can be calculated using the formula v = gt, where g is the acceleration due to gravity (approximately 9.81 m/s^2). After 2 seconds, the velocity is 19.62 m/s downward. After 5 seconds, the velocity is 49.05 m/s downward. After 10 seconds, the velocity is 98.1 m/s downward.
176.4 meters
There are two major steps in solving this problem. First, we have to figure out how long it takes a monkey to fall 10m. Second, we divide the distance from the base of the cliff by the number of seconds to estimate the unfortunate simian's velocity. To get the time the monkey falls, (assuming this is on Earth with gravitational acceleration equal to 9.8 m / s), use the equation d = 4.9t2 . t = sqrt(d/4.9). Filling in the given value for d (10m) we get t = sqrt (10/4.9) which is about 1.43 seconds. If the monkey travelled outward 5m from the edge of the cliff in 1.43 seconds, the furry fellow was going 5m / 1.43s or about 3.5 m/s. Why the monkey chose to do the Acapulco Cliff Dive remains a mystery known only to him, and he is not talking.
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
64 METERSA+
Initial velocity refers to the velocity of an object at the very beginning of its motion or in a particular interval of time. It is typically denoted as "u" in physics equations and is crucial for determining the subsequent motion and trajectory of the object. Initial velocity is an important parameter in analyzing various phenomena such as projectile motion, collisions, and more.
The horizontal speed of the ball can be calculated using the equation: horizontal distance = horizontal speed * time. In this case, the horizontal distance is 40 meters and the time is 4 seconds. Therefore, the horizontal speed of the ball was 10 m/s.