Wiki User
∙ 14y ago176.4 meters
Wiki User
∙ 14y ago10 m/s
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
a. 144 feet b. 96 ft/sec.
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
10 m/s
The height of the cliff can be calculated using the formula for free fall: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time (6 seconds). Plugging in the values, we get h = (1/2)(9.8 m/s^2)(6 s)^2 = 176.4 meters. Therefore, the height of the cliff is 176.4 meters.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
a. 144 feet b. 96 ft/sec.
To calculate the velocity of the ball, we need to know the height from which it was dropped. If the ball was dropped from rest, we can use the formula for free fall motion: velocity = (acceleration due to gravity * time). Assuming the acceleration due to gravity is 9.81 m/s^2, the velocity of the ball hitting the ground after 3.03 seconds would be around 29.7 m/s.
It went off within the minute.
The sound moves in a second 340 metres. That is in 3.8 seconds 1292 metres. But because there is the way down to the ocean and back to the ears of the stone dropper, the distance must be half of it. The cliff is 646 metres high.
Assuming you throw the rock horizontally off the cliff it drops down at the acceletrtion of gravity. height= 1/2 gt^2 With g = 9.8 m/sec and t = 5 seconds we have height = (1/2) (9.8)(5)(5) = 122.5 meters notice it has nothing todo with the 50 meter distance, which depends on the horizontal velocity.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
28.224m
44 meters tall
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.