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A student measured the mass of a small object and found it to be 56.0 grams The object's mass is known to be 55.0 grams What is the percent of error in the student's measurement?
Wiki User
∙ 13y ago
1.8%
Wiki User
∙ 13y ago
The percent error in the student's measurement is calculated as |(measured value - actual value) / actual value| x 100. Plugging in the values, we get |(56.0g - 55.0g) / 55.0g| x 100 = 1.82%. This means the student's measurement is 1.82% higher than the actual value.
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