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Suppose a paper clip is measured at 3 cm What is the percent error in this measurement?
This is a two step problem:
First you must find the Greatest Possible Error (GPE)?
To find the greates possible error, you must acknowledge the significant place value.
In this case because it is measured to 3cm the answer is 1cm.
The GPE is half of 1cm which is 0.5cm.
Second the percent of error is a ratio of the GPE/Original measurement.
In this case it is 0.5/3 is 0.16666666667 therefore the answer is:
approximately 16.67% or 16.7% or 17%
What else can I help you with?
What is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?
.229/.225 = 1.0178 percent error = (1.0178 - 1) times 100 to get to percent = .0178 x 100 = 1.78%
What is the greatest possible error for the measurement 4.7 cm?
If the number of significant digits is correct, this measurement should be between 4.6 and 4.8 and thus have a possible maximum error of 0.1.
What is the greatest possible error for each measurement. 953 mi?
It is 0.5 mi.
What shows you how accurate to the true value an experimental value is?
The error, which can be measured in a number of different ways. Error, percentage error, mean absolute deviation, standardised error, standard deviation, variance are some measures that can be used.
How do you find greatest possible error for measurement of 18.3 m?
It is half the place value of the last digit that is given. In this case, it is + or -0.05m = + or - 5 cm.
What are percent errors?
A percentage error for a measurement is 100*(True Value - Measured Value)/True Value.
If percent error in measurement of mass is 3 percent and percent error in measurement of velocity is 4 percent then what will the percentage error in measurement of kinetic energy?
Kinetic Energy = 1/2 (mass) (velocity)2Measurement of mass is in error by 3%.Measurement of velocity is in error by 4%.If both are low, then KE is measured as(True KE) x (.97) x (.96)2 = 0.894 TKE = 10.6% low.If both are high, then KE is measured as(True KE) x (1.03) x (1.04)2 = 1.114 TKE = 11.4% high.If one is high and the other low, then the net error is in between these limits.
IF The weight of a rock is measured at 2.5 pounds what is the percent error in this measurement?
The percent error is calculated by taking the absolute difference between the measured value and actual value, dividing it by the actual value, and then multiplying by 100. If the actual weight is not provided, the percent error cannot be calculated.
What is the percent error of the measurement 4 cm?
Percent error is calculated by the measured value and the acceped value. For example, if you measure a piece of paper and decide it is 8.45in long, that is your measured value. The package says it is 8.5in long, so it is the accepted value. The formula for percent error is |measured value - accepted value| divided by accepted value ALL times 100.
Which property of a measurement is best estimated from the percent error?
Measurement error: obviously!
Percent error formula?
Divide the calculated or estimated error by the magnitude of the measurement. Take the absolute value of the result, that is, if it is negative, convert to positive. This would make the percent error = | error / measurement |.
A student measured the mass of a small object and found it to be 56.0 grams The object's mass is known to be 55.0 grams What is the percent of error in the student's measurement?
The percent error in the student's measurement is calculated as |(measured value - actual value) / actual value| x 100. Plugging in the values, we get |(56.0g - 55.0g) / 55.0g| x 100 = 1.82%. This means the student's measurement is 1.82% higher than the actual value.
What is the percent error in the measurement of the density of a substance, rounded to the appropriate number of significant figures?
The percent error in the measurement of density is calculated by taking the absolute difference between the measured value and the accepted value, dividing it by the accepted value, and then multiplying by 100. The result is rounded to the appropriate number of significant figures.
A student measured the mass of an object and found it to be 658 grams. The actual objects mass is known to be 755 grams what is the percent error of the measurement?
It is approx 12.8%.
If error in the measurement of momentum of a particle is 100 percent then the error in the measurement of kinetic energy is what?
p=mv %errror in p= %error in m+%error in v lowest value of m=0 hence %error in velocity=100% k.e=%error in mass=2*%error in velocity K.E=200% similarly K.Eminimun=100% total error in K.E = 100+200 =300 hence error in ke = 300%
How do accuracy and precision of measurement affect calculated values and percent error?
The more precise your instruments of measurement are, the less percentage of error you will have.
What should the percent error be in order to accurately assess the level of precision in the measurement?
The percent error should be as close to zero as possible in order to accurately assess the level of precision in the measurement.
