An 8 inch pipe carry how much more volume than 4 inch pipe?

Answer 1

The volume of a cylinder (pipe) is: pi*(r^2)h

If a pipe has an 8 inch radius, then to find the volume you substitute:

V = pi*(8^2)h

If a pipe has a 4 inch radius, then to find the volume you substitue:

V = pi*(4^2)h

Thus, an eight inch pipe can carry 150.72*h more units cubed.

Answer 2

First, you need to find the volumn of the pipe which is L x R2 x Pi; and the units need to be consistent. Let's use inches, since that is the diameter of the pipe. (20 feet x12inches) x 42 x 3.141 = 240inches x 16inches x 3.141 = 12,061.44 cubic inches of volumn in the pipe. There are 231 cubic inches per US gallon - (looked it up on the internet.) Therefore, divide the cubic inch volumn of the pipe by the number of cubic inches per gallon 12,061.44/231= 52.214 gallons. This is the amount of water the pipe can hold.

Answer 3

The volume of a pipe is proportional to the square of its diameter. Since the diameter of the 8-inch pipe is twice that of the 4-inch pipe, the 8-inch pipe can carry four times the volume of the 4-inch pipe.

Answer 4

This can only be answered if the diameter and length of the pipe are known.

RWN exp. pipe is 6in dia by 12in long, The formula is 6x6=36 gives you area x 12in long=432 is volume.