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Yes.

Example:

....................................................

...A * ...........................................

......|.\ ......................................... eg Euler circuit: ACDCBA

......|...\ ........... --------- .............

......|.....\........./...............\............ The Hamilton circuit is impossible as it has two

......|.......\...../...................\.......... halves (ACD & CD) connected to each other only

......|.........\./.......................\........ at vertex C. Once vertex C has been reached in

......|.......C *........................* D.... one half, it can only be used to start a path in

......|........./.\......................./......... the other half, or complete the cycle in the

......|......./.....\.................../........... current half; or if the path starts at C, it will end

......|...../.........\.............../............. without the other half being visited before C is

......|.../ ........... --------- .............. revisited.

......|./ ...........................................

...B *..............................................

......................................................

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12y ago
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6mo ago

Yes, a graph can have an Euler circuit (a circuit that visits every edge exactly once) but not have a Hamiltonian circuit (a circuit that visits every vertex exactly once). This can happen when the graph has certain degree requirements that allow for the Euler circuit but prevent the existence of a Hamiltonian circuit.

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Q: Can a graph have a euler circuit but not a hamiltonian circuit?
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Related questions

What is the difference between a Hamiltonian circuit and a Euler circuit?

In an Euler circuit we go through the whole circuit without picking the pencil up. In doing so, the edges can never be repeated but vertices may repeat. In a Hamiltonian circuit the vertices and edges both can not repeat. So Avery Hamiltonain circuit is also Eulerian but it is not necessary that every euler is also Hamiltonian.


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A Hamiltonian path in a graph is a path that visits every vertex exactly once. It does not need to visit every edge, only every vertex. If a Hamiltonian path exists in a graph, the graph is called a Hamiltonian graph.


What is the difference between an Euler circuit and an Euler path?

The difference between an Euler circuit and an Euler path is in the execution of the process. The Euler path will begin and end at varied vertices while the Euler circuit uses all the edges of the graph at once.


Can a graph have an Euler circuit but not a Hamiltonian circuit?

Yes. An example: _____A---------B________ A connected directly to B and D by one path. _____|_______/|\________ B connected directly to A and E by one path, and to C by two paths. _____|______/_|_\_______ _____|_____/___\_|______ _____|__E/_____\|______ E connected directly to B and D by one path. _____|____\_____C______ C connected directly to B and D by two paths. _____|_____\____|\_____ _____|______\___|__\___ _____|_______\__|__/___ _____|________\_|_/____ _____|_________\|/_____ _____-------------D_____ D connected directly to A and E by one path, and to C by two paths. There is an Euler circuit: ABCDEBCDA But a Hamiltonian circuit is impossible: as part of a circuit A can only be reached by the path BAD, but once BAD has been traversed it is impossible to get to both C and E without returning to B or D first. However there is a Hamiltonian Path: ABCDE.


Find any Hamiltonian circuit on the graph above. Give your answer as a list of vertices, starting and ending at the same vertex. Example: ABCA?

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What is a Euler path or circuit?

An euler path is when you start and one point and end at another in one sweep wirthout lifting you pen or pencil from the paper. An euler circuit is simiar to an euler path exept you must start and end in the same place you started.


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What are some of the accomplishments of Leonhard Euler?

Leonhard Euler is known as a Swiss mathematician and physicist. He made many famously known accomplishments in the area of calculus and graph theory.


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a path that starts and ends at the same vertex and passes through all the other vertices exactly once...


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