Sure, as long as the object is moving at a constant speed.
And by the way ... It's easy to draw a speed/time graph, but
I'm pretty sure it's not possible to draw a velocity/time one.
velocity is nothing but speed of a body in the given direction. suppose if body is moving with constant velocity then VT graph will be parallel to the X -axis, if not then the VT graph is not parallel to the X-axis it means then object is moving with different velocity or it has its dierection or both velocity and aswell as direction.
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
A position-time graph shows the relationship between an object's position and time. The position of the object is typically plotted on the y-axis, while time is on the x-axis. The slope of the graph represents the object's velocity, with a steeper slope indicating a higher velocity.
Not necessarily. The graph of instantaneous velocity versus time may or may not have a Y-axis intercept of zero. It depends on the initial conditions and motion of the object. If the object starts from rest, then the initial velocity is zero, and the graph will have a Y-axis intercept at zero.
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).
If the velocity-time graph is a straight line parallel to the time axis, it means the velocity is constant. The acceleration would be 0 because there is no change in velocity over time.
If an object's velocity-time graph is a straight line parallel to the time axis, then the object's acceleration is zero. This means that the object is moving at a constant velocity.
velocity is nothing but speed of a body in the given direction. suppose if body is moving with constant velocity then VT graph will be parallel to the X -axis, if not then the VT graph is not parallel to the X-axis it means then object is moving with different velocity or it has its dierection or both velocity and aswell as direction.
That the object is moving at a constant velocity
you can't....it's merely impossible! Assuming it is a graph of velocity vs time, it's not impossible, it's simple. Average velocity is total distance divided by total time. The total time is the difference between finish and start times, and the distance is the area under the graph between the graph and the time axis.
The x-axis is time and the y-axis is velocity.
It is a velocity-time graph in which time is plotted along the horizontal axis and the velocity of an object in a selected direction is plotted along the vertical axis.
The graph is parallel to the time axis, normally the horizontal axis.
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
For that period of time, d(t) (the distance) is not changing so the motion is zero velocity.
The problem is that a so-called "velocity-time" graph is really a "speed-time" graph.A complete description of "velocity" at any point in time includes speed and direction,but the graph can only show speed, that is, the magnitudeof velocity, vs. time, butit can't show the direction of the motion. If the direction changes with time, thenthat constitutes acceleration, but we can't discern it from the graph.If the "v-t" graph is a straight line parallel to the time axis, then we know the speed,and therefore the magnitude of velocity, is not changing. If we also know from someother source that the motion is in a straight line, then we may say that the accelerationis zero. But if we have no other information in addition to the graph, we can't reach afull conclusion regarding the acceleration.