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Can you Calculate the empirical formula of the compound made from 43.4 percent Na 11.3 percent C and 45.3 percent O by mass enter the empirical formula?
Crazygal992
Firstly divide percentages by molar mass of that element
Na
43.4/23=1.9
C
11.3/12.01=0.94
O
45.3/16=2.83
Then divide the result of the first step by the smallest answer
Na
1.9/.94=2
C
.94/.94=1
O
2.83/.94=3
Empirical Formula is Na2CO3
Wiki User
∙ 13y ago
The first step is to convert the percentages into grams. Next, determine the number of moles of each element present using their molar masses. Lastly, divide each mole value by the smallest number of moles calculated to find the simplest ratio of atoms, which will be the empirical formula.
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Can the empirical formula be used to calculate the percent composition of a compound?
Yes, the empirical formula can be used to determine the percent composition of a compound. The percent composition can be calculated by determining the molar mass of each element in the formula and then dividing the molar mass of each element by the molar mass of the whole compound, and finally multiplying by 100 to get the percent composition.
An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
Explain why the percent composition of certain compounds are not sufficient to determine the compounds molecular formulas?
The percent composition only tells us the relative proportions of the elements present in the compound, not the specific arrangement of atoms within the molecule. Different compounds can have the same percent composition but different structures, leading to different molecular formulas. For example, both ethanol (C2H6O) and dimethyl ether (C2H6O) have the same percent composition, but are different compounds with distinct structures.
What is the empirical formula of a compound that contains 75 percent Ag and 25 percent Cl by mass?
The empirical formula of the compound would be AgCl, as the ratio of silver to chlorine in the compound is 3:1 based on the given mass percentages (75% Ag and 25% Cl). This ratio simplifies to AgCl when expressed in the simplest whole number ratio.
Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?
Chi a+
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CHI3
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What is the importance of percentage composition?
Percent composition can be used to calculate the percentage of an element/compound in a mixture. From the percent composition, you can also find the empirical formula. And from the empirical formula you can find the actual molecular weight.
How do you know when to solve for a empirical formula?
You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.
What is the percent composition of a compound with the empirical formula CO2?
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
Can the empirical formula be used to calculate the percent composition of a compound?
Yes, the empirical formula can be used to determine the percent composition of a compound. The percent composition can be calculated by determining the molar mass of each element in the formula and then dividing the molar mass of each element by the molar mass of the whole compound, and finally multiplying by 100 to get the percent composition.
What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?
The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.
What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?
The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.
What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?
The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
