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∙ 12y agoP2o5
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∙ 12y agoThe empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.
The empirical formula of this compound would be MgO.
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
The empirical formula of the compound is Na2SO4, which is sodium sulfate. This is because the percentages given closely correspond to the molar ratios in the compound, with a sodium to sulfur to oxygen ratio of 2:1:4.
The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.
The empirical formula of this compound would be MgO.
The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
p2o5
The empirical formula of the compound is Na2SO4, which is sodium sulfate. This is because the percentages given closely correspond to the molar ratios in the compound, with a sodium to sulfur to oxygen ratio of 2:1:4.
The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.
The empirical formula for this compound is CaSO4. This can be determined by converting the percentages to moles, finding the mole ratio, and simplifying the subscripts to the smallest whole number ratio.
The empirical formula for a compound with 40% sulfur and 60% oxygen by weight would be SO3 (sulfur trioxide). This is because the ratio of sulfur to oxygen is 1:3 in this compound.
The empirical formula for a compound represents the simplest whole number ratio of atoms present in a molecule. For the molecular formula N2O4, the empirical formula is NO2 because it shows the simplest ratio of nitrogen and oxygen atoms present in the compound.
As2O3
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
SO3