0
Still curious? Ask our experts.
Chat with our AI personalities
Ezra
Coach
JordanThe conversion of carbon dioxide (CO2) to carbon (C) and oxygen (O2) is a chemical reaction that requires energy input. One way to achieve this conversion is through a process called electrolysis, where an electric current is passed through a CO2 solution to break it down into its elemental components. This process is being researched as a way to reduce CO2 emissions and produce valuable products such as carbon-based fuels or chemicals.
Add your answer:
Earn +20 pts
What is the Balanced symbol equation for carbon plus oxygen equals carbon dioxide?
The balanced symbol equation for carbon plus oxygen yielding carbon dioxide is: C + O2 -> CO2
What is the balanced equation for The total number of grams of CO2 that are produced when 4 grams of C are added to 10.67 grams of O2?
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
According to the equation C plus O2 how many carbon atoms react with 14 molecules of oxygen to form 14 molecules of carbon dioxide?
In the balanced chemical equation for the reaction of carbon (C) with oxygen (O2) to form carbon dioxide (CO2), one molecule of carbon reacts with one molecule of O2 to form one molecule of CO2. Therefore, to form 14 molecules of CO2, 14 molecules of O2 will react with 14 molecules of carbon, containing a total of 14 carbon atoms.
How many moles of CO2 are produced from 5 miles O2?
This is a chemical calculation. 2.5 moles will C reacting with O2.
The total number of grams of CO2 that are produced when 4 grams of C are added to 10.67 grams of O2?
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
