if the acceleration is constant, then it is a parabola (a=V*t+(at^2)/2).
if it isn't, and you are give it's formula in relation to time, then it is possible to find the distance formula by using higher level mathematics(integrals).
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
The shape of a position versus time graph is parabolic when the object is undergoing constant acceleration. This acceleration results in a quadratic relationship between position and time, forming a parabolic curve.
Acceleration can be determined from a velocity-time graph by calculating the slope of the line on the graph. The steeper the slope, the greater the acceleration. If the graph is curved, acceleration can be calculated by finding the tangent to the curve at a specific point.
Motion can be represented graphically using position-time graphs, velocity-time graphs, and acceleration-time graphs. These graphs provide information about how an object's position, velocity, and acceleration change over time. Position-time graphs show the object's position at different times, velocity-time graphs show how the velocity changes over time, and acceleration-time graphs show how the acceleration changes over time.
To determine the average acceleration from a position-time graph, you can calculate the slope of the line connecting the initial and final velocity points on the graph. This slope represents the average acceleration over that time interval.
No, the slope on a position-time graph represents the object's velocity, not acceleration. Acceleration would be represented by the slope of the velocity-time graph.
To determine acceleration from a distance-time graph, calculate the slope of the graph at a specific point. The steeper the slope, the greater the acceleration. The formula for acceleration is acceleration change in velocity / time.
Acceleration can be determined from a position-time graph by calculating the slope of the graph at a specific point. The slope represents the rate at which the position is changing over time, which is the definition of acceleration. A steeper slope indicates a higher acceleration, while a shallower slope indicates a lower acceleration.
A negative acceleration position-time graph indicates that the object is slowing down or decelerating.
Speed can be shown on a graph of position versus time, and acceleration can be shown on a graph of speed versus time.
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
To determine the average acceleration from a velocity-time graph, you can calculate the slope of the line connecting the initial and final velocity points on the graph. This slope represents the average acceleration over that time interval.
A positive acceleration position-time graph indicates that the object is speeding up or moving in the positive direction.
A position-time graph showing positive acceleration indicates that the object is moving in the positive direction and its speed is increasing over time.
A position vs. time graph showing positive acceleration would be a straight line sloping upwards from left to right.