Volume equals circumference cubed over six pi squared. V = C3/6(pi2).
The diameter of a basketball is about 9.5 inches. Find the volume of air inside it in cubic centimeters .Neglect the thickness of the ball.(Note:1in=2.54cm) Step 1. Let D=diameter of basketball, then radius r is D/2 or r=4.75 inches Step 2. Volume of Sphere is Step 3.
It is about 1.2 cubic feet, about 8 inches diameter.
Ten-pin bowling balls usually weigh from about 6 pounds (around 2800 grams) to 16 pounds (about 7200 grams) There are no bowling balls that weigh 200 grams (though such a ball would be leagal as there is no minimum weight) but if there were, the mass of the ball divided by the volume of the ball gives the density. The volume of a standard bowling ball is about 5500 cubic centimeters (I assumed a circumference of 27 inches and calculated from that) 200 / 5500 = 0.036 g/cm3 Compare to the density of air = 0,0012 g/cm3
It is not possible to determine the number of tennis balls without knowing the volume of a single tennis ball. Once you know the volume of one tennis ball, you can calculate the number of balls needed to fill 55444 cubic feet.
It would depend on the size of the tennis balls, but assuming a standard 2.63 cubic inches per ball, you would need approximately 122,321 tennis balls to fill 106.6 cubic feet.
5 inches
9.42 inches
30 inches diameter or 93 inches circumference
This cylinder's volume is 301.59 cubic inches.
Circumference = pi*d = 69 inches
27π cubic inches.
The circumference of a ball is C = diameter times pi. pi = 3.14159 ... So you get the circumference C = 27.4889 inches.
approx. 6.28 in.
A bowling ball has an initial circumference between 26.704 inches and 27.002 inches with a diameter between 8.500 inches and 8.595 inches.
7776*pi cubic inches
The ball is about 11 inches (28 cm) long and about 22 inches (56 cm) in circumference at the center.
2.9.5 inches