Ten-pin Bowling balls usually weigh from about 6 pounds (around 2800 grams) to 16 pounds (about 7200 grams) There are no bowling balls that weigh 200 grams (though such a ball would be leagal as there is no minimum weight) but if there were, the mass of the ball divided by the volume of the ball gives the density. The volume of a standard bowling ball is about 5500 cubic centimeters (I assumed a circumference of 27 inches and calculated from that) 200 / 5500 = 0.036 g/cm3 Compare to the density of air = 0,0012 g/cm3
0.0125
The density of the object is calculated by dividing its mass by its volume. In this case, the density would be 4000g / 20ml = 200 g/ml.
The density is calculated by dividing the mass by the volume. In this case, the density would be 1.6 g/mL (200 g / 125 mL).
Density = mass/volume so in this case 200/1500 = 0.13 g/cm3
To find the volume of the mass, you can use the formula: volume = mass/density. Given the mass is 540 g and the density is 2.7 g/cm³, the volume would be calculated as follows: volume = 540 g / 2.7 g/cm³ = 200 cm³. Therefore, the volume of the 540 g mass is 200 cm³.
0.0125
The density of the object is calculated by dividing its mass by its volume. In this case, the density would be 4000g / 20ml = 200 g/ml.
Your question does not make sense. 200 cubic centimetres is not a measure of mass. Do you mean 200 grams? To find density you divide the mass by the volume.
The density is calculated by dividing the mass by the volume. In this case, the density would be 1.6 g/mL (200 g / 125 mL).
The volume should be 200 cm3, not cm2. Density = Mass/Volume = 120g /200 cm3 = 0.6 g/cm3
The kinetic energy of the bowling ball can be calculated using the formula: KE = 1/2 * m * v^2, where m is the mass and v is the velocity. Plugging in the values, KE = 1/2 * 4 kg * (10 m/s)^2 = 200 Joules.
The force of the bowling ball colliding with the golf ball causes the golf ball to be redirected in an elastic collision. How fast either travels depends on the friction of the surface and the angle of contact with the bowling ball.Comparative Masses and EnergyIn the collision between a golf ball and a bowling ball, the fact that the bowling ball continues to move (although possibly changed in direction) is a function of the comparative masses of the two. The bowling ball is much more massive, so at normal velocities its kinetic energy exceeds the kinetic energy of the golf ball. In order to "stop" the bowling ball, the golf ball would have to make a perfectly aimed collision, and have a much higher velocity. Quantitatively, the velocity of the golf ball would have to be the inverse ratio of the ratio of the masses of the two balls, so that the kinetic energy (mass times velocity) is equal and in the opposite direction.Example : Golf ball at 45 g, ten pound bowling ball at 4500 g -- the golf ball would have to move at 100 times the velocity of the bowling ball to counteract its kinetic energy. If the bowling ball rolls at 2 m/sec, the golf ball would have to travel at more than 200 m/sec (720 kph or 447 mph), about 3 times a ball's normal velocity off the face of a golf club.
Density = Mass/Volume = 100/200 = 0.5 grams per ml.
Density = mass/volume so in this case 200/1500 = 0.13 g/cm3
The density of the object can be calculated using the formula: Density = Mass / Volume. In this case, the mass is 200 grams and the volume is 250 ml (which is equivalent to 250 cm^3). Therefore, the density is 200 g / 250 cm^3 = 0.8 g/cm^3.
200 liters of pure, clean water at standard temperature have 200 kilograms of mass. On earth, that amount of mass weighs 1,960 newtons (440.9 pounds). Credit for this answer goes to Alcohen2006
Density = mass/volume , so 200/50 = 4 g / cubic cm.