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How do you make an acceleration time graph from the data of a velocity time graph?
Wiki User
∙ 11y ago
take the slope of every change in the velocity time graph and plot it
Wiki User
∙ 13y ago
Wiki User
∙ 11y agoPlot the first derivative of the velocity time graph.
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How is deceleration represented on a velocity per time graph?
It is radial the velocity in a direction towards or away from a fixed point of reference (the origin) at a given time. The velocity time graph takes no account of motion in a direction across the radial direction.
Graphical representation of motion?
Position-Time GraphYou can graph motion on a position vs time graph. On a position vs time graph, position is on the y-axis and time is on the x-axis. If the velocity is constant, the graph will be a straight line and the slope is average velocity. If the motion is accelerating, the graph will be a curved line.Velocity-Time GraphYou can also graph motion on a Velocity-Time graph. On a velocity vs time graph, velocity is on the y-axis, time is on the x-axis. If the graph is a straight line, velocity is constant and the slope is average acceleration. Also, on a velocity vs time graph, the area under the line is displacement.Refer to the related link for illustrations of the different graphs of motion and their meanings.
How to calculate distance from a velocity time graph?
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown. For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector. All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
What does analyzing data in graphs and charts allows you to do?
hi I'm Robert the answer to this question is that when scientists collect data they are often trying to find out whether certain factors changed or rein the same. Often, the simplest way to do that is to record the data in a table and then make a graph. Although you may be able to detect a pattern of change from a data table. One way to record data from an experiment is by using a data table. Then, the data may be plotted on a graph to make it easier to interpret.
How do you find distance when given initial velocity final velocity and acceleration?
Here are the velocity equations D= (vi+vf/2)t D=vit + 1/2 at^2 V^2=Vi^2 + 2ad V= vi+at a= (vf-vo)/t According to your question, use V^2=Vi^2 + 2ad v= Final velocity vi= initial velocity a= acceleration d= displacement
How do you make a velocity vs time graph from an acceleration vs time graph?
Your acceleration vs. Time graph is the slope of your velocity vs. time graph
How is deceleration represented on a velocity per time graph?
It is radial the velocity in a direction towards or away from a fixed point of reference (the origin) at a given time. The velocity time graph takes no account of motion in a direction across the radial direction.
Graphical representation of motion?
Position-Time GraphYou can graph motion on a position vs time graph. On a position vs time graph, position is on the y-axis and time is on the x-axis. If the velocity is constant, the graph will be a straight line and the slope is average velocity. If the motion is accelerating, the graph will be a curved line.Velocity-Time GraphYou can also graph motion on a Velocity-Time graph. On a velocity vs time graph, velocity is on the y-axis, time is on the x-axis. If the graph is a straight line, velocity is constant and the slope is average acceleration. Also, on a velocity vs time graph, the area under the line is displacement.Refer to the related link for illustrations of the different graphs of motion and their meanings.
Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?
When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!
When can you have no acceleration?
To make acceleration equal zero. The velocity must be constant. For example, if velocity is constant at 10 m/s^2 its acceleration is zero. The same is true if velocity is 0 m/s^2.
What increment would be appropriate to make a graph of the data?
what incrament would ba a apppropriate to make a graph of the data
Why make a velocity time graph?
Because its really fun :)
Do you need a data file to make a bar graph?
No but you do need a dataset or data range with which to to populate the graph.
Is a data file needed to make a bar graph Explain?
Yes because you need the data on the right and across the bottom to make the graph
What does the slope of a distance vs time squared graph represent?
That's unusual. I guess your teacher is trying to make you think a bit. It's a good mental exercise, though. You may recall that the units of acceleration are meters per second squared. That gives you a clue right there. And if you knew Calculus, you'd know that acceleration is the second derivative of distance, s, with respect to time, t: d2s/dt2. So, by now you're probably getting the feeling that the slope of a distance-time squared graph has something to do with acceleration. And you'd be right. Just as the slope of a velocity-time graph is acceleration, the slope of a distance-t2 graph is acceleration. Well, not quite. It's actually ONE HALF the acceleration.
If the instantaneous velocity of an object is constant then so is acceleration.?
the velocity increases at a constant rate
Can you make graphs from databases?
As long as you have your data in a data table and you know how to make a graph, yes.
