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You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown.
For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector.
All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
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DevinTo calculate distance from a velocity time graph, find the area under the velocity-time curve. If the graph is above the time axis, sum the areas of each individual shape formed between the curve and the time axis. If the graph is below the time axis, subtract the areas of the shapes below the time axis from the areas above the time axis.
For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector.
All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown.
For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector.
All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown.
For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector.
All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown.
For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector.
All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.
You can find the displacement of an object given a velocity-time graph, not an acceleration-time graph. The area under the shaded regions between the line and the time-axis represent the displacement during the stated time interval.
Refer to the related link for an illustration.
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Calculate distance from a velocity time graph?
To calculate distance from a velocity-time graph, you would find the area under the curve, as this represents the displacement or distance traveled. If the graph is above the time axis, calculate the area above the time axis, and if it dips below, calculate the area below the time axis. Summing these two areas will give you the total distance traveled.
When do two different distance-time graphs have matching velocity-time graphs?
Two different distance-time graphs have matching velocity-time graphs when the slope of the distance-time graph represents the velocity in the velocity-time graph, as velocity is the derivative of distance with respect to time. This means that the steeper the distance-time graph, the greater the velocity on the velocity-time graph at that point.
How is the velocity-time graph related to the distance traveled?
The distance traveled can be calculated by finding the area under the velocity-time graph. The slope of the graph at any point represents the acceleration of the object. The steeper the slope, the greater the acceleration.
How do you go from a position graph to a velocity graph?
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
Can a position time graph be created from a velocity time graph?
Yes, a position-time graph can be created from a velocity-time graph by integrating the velocity values over time. By finding the area under the velocity-time curve, you can determine how the position of an object changes over time.
