There are several ways, depending on the form of linear equation you want. I prefer the slope-intercept form, y = mx + b. Given two points, (x1, y1) and (x2, y2), we can calculate the values of m and b. The slope is m = (y2 - y1)/(x2 - x1). Plugging this and the coordinates of one of the points (say, (x1, y1)), we get
b = y1 - mx1.
But you are probably more interested in the two point form (for obvious reasons). This is basically an equation of the slope at a general point (x, y) with that at (x2, y2), namely (y - y1)/(x - x1) = (y2 - y1)/(x2 - x1).
To write a linear equation given two points, you can first calculate the slope using the formula: slope = (y2 - y1) / (x2 - x1). Once you have the slope, you can choose one of the points to substitute into the point-slope form of a linear equation: y - y1 = m(x - x1), where m is the slope and (x1, y1) is one of the points.
write down the major points in an article. =]
The balanced chemical equation for the oxidation of sucrose (C12H22O11) can be written as: C12H22O11 + 12 O2 → 12 CO2 + 11 H2O.
The equation 2X - y - 8 = 0 can be rearranged into standard form as 2X - y = 8. In standard form, the variables are typically placed on the left side of the equation with the constant on the right, without any x or y terms on the same side as the constant.
2111.Equation coefficients are needed to write a correct chemical equation
write chemical equation for the reaction between viscose solution and sulphuric acid
the Equation of a Line Given That You Know Two Points it Passes Through.
The standard form of a linear equation is y = mx + bwhere m is the slop of the line, and b is the y intercept.If you have two points (x1,y1) and (x2,y2), you can get the slope with the following formula:m = (y2-y1)/(x2-x1)if you plug this number in to the equation you can then plug in any (x,y) point on the line to solve for b.
You write it as: y = 5x-4 Then you calculate a few sample points, plot them, and draw a straight line through them. Since the equation is linear, two points are enough, in theory, but it is usually recommended to plot a third point, as a verification.
If you mean points of (3, 4) and (5, 8) then the slope is 2 and the equation is y=2x-2
No, a calculator is useless, unelss you are dealing with values for x and y which require some difficult working out. Use the general form of a linear equation using two points on the line: y - y1 = (y1 - y2)/(x1 - x2)(x - x1), where the points given are (x1, y1) and (x2, y2).
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You just write, "No Solution."
Identify a linear equation in standard formUse the properties of equality to write a linear equation in standard formDetermine solutions of a linear equation given in standard formGraph a linear equation given in standard form
you add 1+1= 25 simple ;)
If there are given two points, (x1, y1) and (x2, y2), then you can write the equation of a line by finding the slope first [slope = m = (y2 - y1)/(x2 - x1)] and using one of the points in order to write the equation in the point-slope form such as(y - y1) = m(x - x1)y - y1 = mx - mx1y = mx - mx1 + y1y = mx + (y1 - mx1) the slope-intercept form, where m is the slope and (y1 - mx1) is the y-intercept.mx - y = mx1 - y1 the general form of the equation of the line.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
A Y-intercept and the slope. The y-intercept is where the line crosses the Y axis.