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Steve0.3y + 1.2 = 0.4 x
Hence
0.4x - 0.3y - 1.2 = 0
or
0.4x - 0.3y = 1.2
To remove the decimal point multiply by '10' Hence
4x - 3y = 12
Make 'y' the subject
3y = 4x - 12
y = (4/3)x - 4
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