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How high is the window above the ground if a ball drops and strikes the ground 2.00 seconds later?
Wiki User
∙ 14y ago
As , s = ut + 1/2 a t2 , since a ball is dropped , the equation is modified as
h = ut + 1/2 g t2
Therefore , h = 0 x t + 1/2 x 9.8 x 22 [ u = 0 ,since the ball is at rest]
h = 19.6 meters
Height of the window = 19.6 meters
Wiki User
∙ 14y ago
The height of the window above the ground can be calculated using the equation h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time taken (2.00 seconds). Plugging in the values, h = (1/2)(9.81)(2)^2 = 19.62 meters. Therefore, the window is 19.62 meters above the ground.
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A ball dropped from a window strikes the ground 2.00 seconds later how high is the window above the ground?
Using the equations of motion, the height of the window above the ground can be calculated. Assuming the ball falls vertically under gravity, the equation h = (1/2)gt^2 can be used, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time (2.00 seconds). Substituting in the values gives h = (1/2)(9.8 m/s^2)(2.00 s)^2 = 19.6 meters.
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A ball dropped from a window strikes the ground 2.00 seconds later how high is the window above the ground?
Using the equations of motion, the height of the window above the ground can be calculated. Assuming the ball falls vertically under gravity, the equation h = (1/2)gt^2 can be used, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time (2.00 seconds). Substituting in the values gives h = (1/2)(9.8 m/s^2)(2.00 s)^2 = 19.6 meters.
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