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A ball dropped from a window strikes the ground 2.00 seconds later how high is the window above the ground?
Wiki User
∙ 14y ago
As , s = ut + 1/2 a t2 , since a ball is dropped , the equation is modified as
h = ut + 1/2 g t2
Therefore , h = 0 x t + 1/2 x 9.8 x 22 [ u = 0 ,since the ball is at rest]
h = 19.6 meters
Height of the window = 19.6 meters
Wiki User
∙ 14y ago
Using the equations of motion, the height of the window above the ground can be calculated. Assuming the ball falls vertically under gravity, the equation h = (1/2)gt^2 can be used, where g is the acceleration due to gravity (9.8 m/s^2) and t is the time (2.00 seconds). Substituting in the values gives h = (1/2)(9.8 m/s^2)(2.00 s)^2 = 19.6 meters.
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How high is the window above the ground if a ball drops and strikes the ground 2.00 seconds later?
The height of the window above the ground can be calculated using the equation h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time taken (2.00 seconds). Plugging in the values, h = (1/2)(9.81)(2)^2 = 19.62 meters. Therefore, the window is 19.62 meters above the ground.
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How high is the window above the ground if a ball drops and strikes the ground 2.00 seconds later?
The height of the window above the ground can be calculated using the equation h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time taken (2.00 seconds). Plugging in the values, h = (1/2)(9.81)(2)^2 = 19.62 meters. Therefore, the window is 19.62 meters above the ground.
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