Suppose G gallons are used.
Before mixing, you have
5*65 + G*120 = 325 + 120G gallon-degrees.
After mixing, you have
(5+G)*70 gallon-degrees
So 325 + 120G = (5+G)*70 = 350 + 70G
So 50G = 25
G = 0.5 gallons.
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
Water's Freezing point is 32 Degrees Celsius.
25
300
Roughly 4.18400 joules Raising 1 gram of water 1 degree c requires 1 calorie (the definition of calorie includes the actual starting temperature, I think something like 3 degrees celsius). 1 calorie = 4.18400 joules
Assuming that you are using the near obsolete units for measuring temperature, the answer is 180 gallons at 100 degrees Fahrenheit.
how hot is the boiling water? That makes a big difference? (is that a homework question?) I'm just trying to apply logic here, bear in mind there may be some special properties that you may have to account for like the glass/plexiglas that the water is in will have to have its temp raised also. So here goes... Raising 500 gallons of water 20 degrees would seem to require a combined value of 10,000 degrees (500 gallons times 20 degrees). So first you need to know the temperature difference between the existing water and boiling. Then devide the resulting difference into the 10,000 degrees for your simplistic answer. However, it is a bit more complicated if the tank is full at 500 gallons because you have no room to add the boiling water. That is, it would roughly take 62 gallons of boiling water to raise 500 gallons of 50 degree water to 70 degrees and the tankwouyld obviously overflow. So if it was already full you would have had to remove 62 gallons first leaving 438 gallons and consequently reducing your degree needs to 8760 degrees which means if you add the 62 gallons of boiling water you would have ended up with 72.7 degree water. So, I'd reduce the capacity to 445 gallons and add 55 gallons of boiling water and you should be pretty close.
That all depends on what you want the final temperature of the mixture to be. Technically, one single drop of 40-degree water will reduce the temperature of the 800 gallons.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
U.S.gallon = 8.33 pounds of water. Therefore to raise the temperature by one degree F will require 8.33 BTU. The initial temperature of 50 F is inconsequential.
A watt is a unit of power: what is required is probably the amount of energy - which is measured in joules.
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
probably more than one second
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
Depends on how high you want to raise the gram of water ;).
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.