The determining factor is that the maximum unbalanced neutral current must not exceed 20 amperes. If all circuits are on the same phase, or hot leg, you would be limited to one. That's because two 20A circuits on the same phase would cause 40A of neutral current to flow. Very bad... If you have a 240 volt Edison type service with two hot legs (typical in US homes), and you use one circuit from each hot leg, you are allowed two. If you load one or the other circuit to 20A, the maximum neutral current would be 20A. If you load both circuits to 20A at the same time, the neutral current falls to zero because the two legs balance each other out. No matter how you load the two circuits (as long as each does not exceed 20A), the neutral current will never exceed 20A. If you have three-phase power, then you are allowed three circuits, as long as they are one from each phase, for the same reason as above. Of course, all this is technically accurate, and will work, but you must also check your local electrical code, because most have some specific rules and exceptions to the above. Be legal, be safe! IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS. If you do this work yourself, always turn off the power at the breaker box/fuse panel BEFORE you attempt to do any work AND always use a meter or voltage indicator
to insure the circuit is, in fact, de-energized.
In theory, 20 amps at unity power factor (pure resistive load, no motors or Transformers), although it is good practice to not load circuits to 100% capacity. Also consider that many loads draw more current for transients than in normal operation--for example an incandescent lamp will pull a lot more current when first turned on and when the filament breaks.
A 20 amp breaker is designed to trip when it detects a current over 20 amps. Now it takes a small but finite time to recognize this excess current and trip. So given the duration of the over current spike it could be over 20 amps for a small fraction of a second before tripping. However, given that a very sharp spike could exceed 20 amps, there is also a limit for a continuous load and this is 80% of the rated amount. In this case 16 amps continuous.
1.9 amps
To calculate the number of amps, you need to know the voltage of the circuit. Using the formula Amps = Watts / Volts, if the voltage is 120V, then 9.8kW at 120V would be approximately 81.67 amps.
1 amp
To calculate the amps for a given amount of watts, you need to know the voltage of the circuit. If we assume a typical household voltage of 120V, then the calculation would be 9000 watts / 120V = 75 amps.
To calculate the watts needed for 26 amps, you would multiply the amperage by the voltage. For example, if the voltage is 120V, the calculation would be 26 amps x 120V = 3120 watts.
1.9 amps
To calculate the number of amps, you need to know the voltage of the circuit. Using the formula Amps = Watts / Volts, if the voltage is 120V, then 9.8kW at 120V would be approximately 81.67 amps.
1 amp
To calculate the amps for a given amount of watts, you need to know the voltage of the circuit. If we assume a typical household voltage of 120V, then the calculation would be 9000 watts / 120V = 75 amps.
How many Amps is the fridge pulling? Multiply the Amps by the 120V circuit you're plugging into and you'll get your Watts.
To find the power will depend on the voltage the item uses. Assuming a 120 volt circuit divide the wattage by the voltage, this gives the amps used. 2000w / 120v = 16.67 amps. 1500w/ 120v = 12.5 amps used.
To calculate the watts needed for 26 amps, you would multiply the amperage by the voltage. For example, if the voltage is 120V, the calculation would be 26 amps x 120V = 3120 watts.
The maximum wattage for a 120V outlet is typically around 1800 watts. This is because the standard amperage for a 120V outlet is 15 amps, and power (watts) is calculated by multiplying voltage by amperage.
Your normal house outlets will be either 15 amps or 20 amps. It is suggested that you don't exceed the rating of the protecting breaker by more than 80%. That would be 12 and 16 amps respectively. It may work on 15 A circuit, but if anything else ins plugged into the same circuit it might blow.
To calculate the amperage, you need to know the voltage of the circuit. If you assume a standard 120V circuit, you can use the formula: Amps = Watts / Volts. For 6500 Watts on a 120V circuit, it would be approximately 54.17 Amps.
To calculate the amperage for 4 kW, you would need to know the voltage of the circuit. However, assuming a standard voltage of 120V, you can use the formula: amps = watts / volts. Therefore, for 4 kW at 120V, the amperage would be approximately 33.33 amps.
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.