assuming you mean a standard cubic foot of air
1 scf = 1 cu.ft. of air at 60F at 14.696 psia at sea level
assuming the tank of air is at 60F and at 1 atmosphere ambient pressure and 60F ambient temperature
then the equation V = P'V'/P is used to determine the volume of air compressed into the tank
so:
V = (125 psig + 14.696psia)(5gal x 230.9 cu.in./gal./1728 cu.in./cu.ft.)/14.696psia
V = (139.696 psia)(.66811 cu.ft)/14.696 psia
V = ~6.350 standard cu. ft. of air compressed into the tank
* a change in ambient temperature, tank temperature, tank pressure or atmospheric pressure will change the actual volume of air compressed.
There are approximately 4.24 cubic feet in a 20 gallon propane tank.
The tank has a volume of 3,456 cubic inches. To convert this to gallons, divide by 231 since there are 231 cubic inches in a gallon. Therefore, the tank holds approximately 14.96 gallons.
a standard 10 gallon tank is 20 inches long.
To convert gallons to cubic inches, you would multiply by 231 (since there are 231 cubic inches in a gallon). So, 13.6 gallons would be 13.6 x 231 = 3141.6 cubic inches.
* Calculate the volume of the storage tank (area of base x perpendicular height). * Area of the base = pi times radius squared, * so if the diameter is 10 feet, then the radius is 5 feet. * 5 times 5 times pi = 78.5 square feet. * If the height is 10 feet, then the volume is area (78.5) times height (10) = 785 cubic feet. * 1 cubic foot = 7.48 gallons, so * 785 cubic feet = (785 times 7.48) = 5871.8 gallons.
That would be approximately 6 cubic feet.
1 cubic feet equals 7.48 gals. So 60 gallons equals 8.021390374 cubic feet. 1 cubic feet equal 1728 cubic inches. The answer would be 13,860.96256 cubic inches in a 60 gallon tank.
There are approximately 4.24 cubic feet in a 20 gallon propane tank.
25
4010.7 cubic feet.
To determine how many yards of sand are needed to fill a 275-gallon oil tank, first, convert gallons to cubic yards. There are 27 cubic feet in a cubic yard and 7.48 gallons in a cubic foot. Thus, 275 gallons is approximately 37 cubic feet (275 ÷ 7.48). Dividing by 27 yields about 1.37 cubic yards. Therefore, you would need approximately 1.37 yards of sand to fill a 275-gallon oil tank.
A 44-inch diameter 500 cubic Imperial gallon cylindrical tank is 47.4 feet long.
600 US gallons = 138,600 cubic inches = 80.208333... cubic feet = 2.9707 cubic yards. (rounded)
882.9 cubic feet.
To calculate the volume of the oil tank in cubic inches, you first need to convert the volume from gallons to cubic inches. There are 231 cubic inches in a gallon, so 275 gallons would be 275 x 231 = 63,525 cubic inches. Therefore, a 275-gallon oil tank would have a volume of 63,525 cubic inches.
If the tank is a cylinder, 72 feet in diameter and 4 feet deep, that works out to 121,827.862 U.S. gallons. 1 U.S. gallon is exactly 231 cubic inches, so a cubic foot is about 7.48 gallons.
Usually the dimensions are 6 ft x 2 ft x 2ft.