The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
80 lbs until past 45 degrees
1 horsepower = 550 foot-pounds per second 30 inches = 2.5 feet (2.5) x (220)/10 = 550 foot pounds per 10 seconds = 1/10th of a horsepower.
Assuming the pivot is positioned at a 90-degree angle and ignoring friction, it would take a 100-pound force applied at the end of a 1-foot-long lever arm to lift 100 pounds. This is based on the principle of torque, where the force applied multiplied by the distance from the pivot point determines the weight that can be lifted.
Macho Matt can lift 200 kilograms with ease. How much is this in pounds?
(1,500 pounds) x (60 inches) / (12 inches per foot) = 7,500 foot-pounds
1500 or less
The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
To lift a 2-ton elephant, which is equivalent to 4000 pounds (2 tons x 2000 pounds/ton), you would need a force greater than 4000 foot-pounds. This is because the force required would depend on multiple factors such as the distance the elephant needs to be lifted and the efficiency of the lifting mechanism.
Yes. Work is measured in foot-pounds, so 300*1 = 100*3 = 300 foot-pounds. ■
33" tire is what we recomend
yes you can run 35inch tire as long as you put them on an 8inch rim. i have that size on my 1999 dodge ram 1500 4 door.
you shoul only need to extend you body to frame grounds. but generally that is only with a big lift
you shouldn't have to use any lift at all. i have 24s on my 2000 1500 ext. cab and have no trouble with rubbing. doesnt like to stop though
That takes 80 foot-pounds, equivalent to about 59 joules.
800
4 inch body lift or 6 inch frame lift