You cant answer this unless you have proper measurements. Assuming that the pipe is a cylinder, using the equation V=(pi) r2 L
Where (pi) is 3.14159 and r is the radius of the pipe and L is the length of the pipe.
The question asks for Gallons, a unit of Volume. What is given is the length and width, used to find an area.
This pipe will hold 1,468.8 gallons of water.
There are 22.85 gallons in a waste line which is 2 inches in diameter and is 140 feet long. This can be calculated as pi * r *r *length *7.48051 where r and length are both expressed in feet. (pi = 3.14159265).
A 2.5 inch fire hose has a capacity of approximately 60 gallons per 100 ft. Therefore, a 50 ft hose would hold around 30 gallons of water.
The pipe would need to be 10 feet 10.8 inches long.
The volume of a cylinder is (pi ) R2 L.R = 1/2 diameter = 15 inchesL = 25 feet = 300 inches1 gallon = 231 cubic inchesVolume in gallons = (pi) R2 L / 231 = 917.998gallons (rounded)
A 72-inch pipe 16 feet long holds up to 3,384.1 US gallons of water.
14.7 gallons of water.
111 gallons of water.
12,239.9 gallons of water per 3,000 feet.
5.5 gallons per 15 feet of 3-inch pipe.
6.5 US gallons of water.
1.6 gallons of water.
Up to 1,795.2 gallons of water.
65.3 gallons or 8.7 cubic feet.
40.8 gallons of water per 10 feet of length.
This pipe will hold 1,468.8 gallons of water.
45.9 US gallons.