How many gallons of water will a 8 inch pipe that is 20 feet long hold?

Answer 1

Well, isn't that a lovely question? Let's paint a happy little picture here. An 8-inch pipe that is 20 feet long can hold approximately 37.3 gallons of water. Isn't that just delightful? Just imagine all the happy little fishies that could swim around in there.

Answer 2

To calculate the volume of water that a cylindrical pipe can hold, we can use the formula for the volume of a cylinder: V = πr²h, where r is the radius and h is the height. First, convert the diameter of the pipe from inches to feet: 8 inches = 8/12 feet = 0.67 feet. The radius (r) of the pipe is half the diameter, so r = 0.67/2 = 0.335 feet. Now, we can calculate the volume of water that the pipe can hold: V = π(0.335)²(20) = π(0.112)²(20) ≈ 0.706 ft³. Finally, convert this volume into gallons (1 ft³ = 7.48 gallons): 0.706 ft³ * 7.48 gallons/ft³ ≈ 5.28 gallons. Therefore, the 8-inch pipe that is 20 feet long will hold approximately 5.28 gallons of water.

Answer 3

That completely depends on the length of the pipe.

Answer 4

2.61 gallons per foot.

The answer depends on material type the pipe is made out of and the wall thickness of the pipe.

Answer 5

52.2 gallons of water.

Answer 6

32 ok 32

Answer 7

19