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How many grams HBr are required to produce 150g AlBr3 in the equation 2Al plus 6HBr producing 2AlBr3 and 3H2?
Wiki User
∙ 11y ago
Given the balanced equation
2Al + 6HBr --> 2AlBr3 + 3H2
In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).
150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr
----------- 266.6g AlBr3 * 2 molecules AlBr3
Wiki User
∙ 11y ago
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Why is a balanced equation for Al plus Br-- and gt AlBr3?
AlBr3 is the product thus: 2 Al + 3 Br2 ------> 2 AlBr3 Aluminum has the anion charge of 3+ and a bromine atom has just 1+ thus you need 3 bromine atoms in order to make the product and end up with a non-charged molecule. Unfortunately bromine comes in its diatomic (two of the same atom) in this equation thus you can't have 1.5 of those molecules. If you multiply in such a way, in this case by two, to make everything whole numbers you have your equation.
How do you balance the equation for Cl plus AlBr3 ---- Br plus AlCl3?
2Fe+3Cl2------>2FeCl3
What is the balanced equation for Aluminum chloride and barium hydroxide gas to form aluminum hydroxide and barium chloride?
Al2(SO4)3 + 6KOH --> 2 [Al(OH)3](s) + 3K2SO4or in excess hydroxide:Al2(SO4)3 + 8KOH --> 2K+ + 2 [Al(OH)4]-(aq) + 3K2SO4
What is the equation for aluminum bromide plus chlorine yield aluminum chloride plus bromine?
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
What is the woed equation for the reaction of aluminium and bromine?
The reaction between aluminum and bromine is represented by the chemical equation: 2Al + 3Br2 → 2AlBr3
What is aluminum metal and diatomic bromine chemical equation?
The chemical formula for aluminum metal is Al. The chemical formula for diatomic bromine is Br2. The balanced chemical equation for the reaction between aluminum and diatomic bromine to form aluminum bromide is: 2Al + 3Br2 -> 2AlBr3.
What is the balanced equation for Potassium bromide and aluminum nitrate?
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
What is aluminum bromide plus chlorine yields aluminum chloride and bromine?
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2. In this reaction, aluminum bromide reacts with chlorine gas to produce aluminum chloride and elemental bromine.
What is the chemical equation for bromine plus aluminum iodide?
The chemical equation for bromine reacting with aluminum iodide is: 2AlI3 + 3Br2 -> 2AlBr3 + 3I2
Aluminum metal reacts with bromine gas?
Aluminum metal reacts with bromine gas to form aluminum bromide. This is a redox reaction where aluminum is oxidized and bromine is reduced. The balanced chemical equation for this reaction is 2Al + 3Br2 -> 2AlBr3.
What is the chemical formula for aluminium bromide plus chlorine yield aluminium chloride plus bromine?
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.
Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas?
The reaction between aluminum bromide and chlorine gas forms aluminum chloride and bromine gas. This is a double displacement reaction where the bromine from aluminum bromide is replaced by chlorine to form new compounds. The balanced chemical equation for this reaction is 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.
How many grams of aluminum bromide are formed by the reaction of 121 g of HBr according to the equation?
The balanced chemical equation is: 6HBr + Al2(SO4)3 -> 2AlBr3 + 3SO3 + 6H2O. To find the grams of aluminum bromide formed, you need to calculate the molar ratio of HBr to AlBr3 and then convert 121g of HBr to grams of AlBr3.
Al2O3 plus HBr AlBr3 plus H2O?
Al2O3 + 6HBr = 2Albr3 + 3H2O
Solid aluminum metal and diatomic bromine liquid react spontaneously Give the chemical equation including phases that describes this reaction?
First we need to determine whether this is a combination, combustion, or decomposition reaction.It's classified as a combination.Next we need to determine the correct formulas for the reactants.These would be Al(s) and Br2(l)Next, we need to identify the product of this reaction, which would be AlBr3Lastly, we need to balance the equation.Your final answer will be:2Al(s) + 3Br2(l) --> 2AlBr3(s)
