None. This is a metathesis reaction, and thus nothing is produced but a combination of the reactants (NH4Br, for example).
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Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
When hydrogen bromide (HBr) reacts with sodium hydroxide (NaOH), the products formed are sodium bromide (NaBr) and water (H2O). The balanced chemical equation for this reaction is: HBr + NaOH -> NaBr + H2O.
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
The balanced chemical equation is: 6HBr + Al2(SO4)3 -> 2AlBr3 + 3SO3 + 6H2O. To find the grams of aluminum bromide formed, you need to calculate the molar ratio of HBr to AlBr3 and then convert 121g of HBr to grams of AlBr3.
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
This equation is:HBr + LiOH = LiBr + H2O
The equation for the reaction between hydrobromic acid (HBr) and water (H2O) can be represented as: HBr + H2O → H3O+ + Br-. This reaction involves the transfer of a proton from HBr to water, resulting in the formation of hydronium ion (H3O+) and bromide ion (Br-).
HBr dissociates in water to form H3O+ and Br-. The net ionic equation is H+ + Br- -> HBr.
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
Al2O3 + 3HBr -> Al2Br3 + 3H2O Aluminium tribromide is readily hydrolysed so the hypothetical end product will react further to give a mix of AlBr(OH) compounds. The best preparation is Al metal plus bromine.
When potassium bicarbonate (KHCO3) reacts with hydrobromic acid (HBr), the products formed are potassium bromide (KBr), water (H2O), and carbon dioxide (CO2).
The reaction of 2Br2 + 2H2O → 4HBr + O2 involves the oxidation of bromine (Br2) by water (H2O) to form hydrogen bromide (HBr) and oxygen (O2). Bromine is reduced to HBr, and oxygen gas is released as a byproduct.