Ohm's Law states Volts = Amps x Resistance.
You would need to apply 600 volts across 3 ohm load to have 200 Amps flow in circuit.
Not sure what you are really asking and why you mentioned 2 gauge.
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To calculate the voltage drop in a circuit, you can use Ohm's Law (V = I * R). In this case, V = 200 amps * 3 ohms = 600 volts. This means that with a 200 amp current flowing through a 3 ohm 2-gauge wire, there will be a voltage drop of 600 volts.
I'm assuming this is standard residential single phase. Simple calculation as noted below: Watts / Volts = Amps So: 200 Watts / 120 Volts = 1.666~ Amps If you needed to calculate for a 220 volt run with the same 200 Watts 200 Watts / 220 Volts = 0.909~ Amps Remember 80% load per circuit breaker so a 15 amp breaker you should only load to 12 amps or less. Using Watt / Volts = Amps is the same as Amps x Volts = Watts. 15 Amps X .8 (80%) = 12 Amps max per circuit (for a 15 amp breaker/fuse) So 12 Amps x 120 Volts = 1440 Watts max for a 15 amp circuit (typical 14 gauge wire) *************************************************************** If a 20 amp circuit and 12 gauge wire (smaller gauge = larger dia wire). 20 Amps X .8 (80%) = 16 Amps max per circuit So 16 Amps x 120 Volts = 1920 Watts max for a 20 amp circuit (typical 12 gauge wire)
The formula to calculate the relationship between amps, volts and watts is Volts X Amps = Watts or Volts = Watts / Amps or Amps = Watts / Volts therefore; 200 Watts divided by 1.95 Amps is 102.5641 Volts.
To convert watts to amps, you can use the formula: Amps = Watts / Volts. In this case, to convert 200 watts at 12 volts to amps, it would be: 200 watts / 12 volts = 16.67 amps. So, 200 watts at 12 volts is approximately 16.67 amps.
No. For an example using a 3500 watt element. The amperage through the element will be I = W/E, 3500/120 = 29 amps. The resistance of this 3500 watt element will be R = E/I, 120/29 = 4.13 ohms. Now using the 200 volts and finding the amperage I = E/R, 200/4.13 = 48 amps. The new wattage of the element has become W = A x V, 48 x 200 = 9600 watts. The element will not stand the increase in amperage and will burn open. To operate on 200 volts and still have a 3500 element in the tank you will have to find an element with a resistance of 12 ohms. I = W/E, 3500/200 = 17 amps. R = E/I = 200/17 = 12 ohms. This is a resistance three times more than the 120 volt element to achieve the 3500 watt rating.
To calculate the amperage, you can use the formula: Amps = Watts / Volts. In this case, 2400 watts divided by 12 volts equals 200 amps. So, 2400 watts at 12 volts would draw 200 amps of current.