539 calories per gram for heat of vaporization plus 1 cal/gram/degree C
100 degrees C - 80 degrees C = 20 degrees C
(539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
To answer this, it is needed to convert one of the temperatures to the same scale as the other. To convert oC to oF, the formula is: F = 9 x C / 5 + 32 So 12oC in Fahrenheit is: F = 9 x 12 / 5 + 32 = 53.6 12oF is less than 53.6oF = 12oC. So 12oF is colder than 12oC.
Approx 2940 Joules.
1 calorie increases 1 gram of water by 1 degree celsius. 4.18 Joules are needed to increase the temperature of 1 gram of water by 1 degree celsius. To reduce the 1 gram of water 1 degree celsius it would have to give off 1 calorie of energy. To calculate the energy multiply the mass in grams of water by 4.18 and by the change in temperature. The energy = 4.18 x m x change in T. The answer is in Joules. If you are using calorie as the unit of energy, replace 4.18 J by 1 C. Note that food is measured in kilocalories (Calories) not metric calories.
Approx. 600 - 800 degrees C / 1,100 - 1,500 degrees F
Yes, ice melts at 0 degrees Celsius (32 degrees Fahrenheit) and boils at 100 degrees Celsius (212 degrees Fahrenheit at sea level). These are the specific temperatures at which the phase transitions occur for water.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
Because degrees Celsius means the same as degrees centigrade, the answer is 18 degrees. Better use the correct word "degrees Celsius."
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The process involves increasing the temperature of water from 8°C to 100°C and then changing its phase to steam at 100°C. The total heat energy required can be calculated using the specific heat capacity of water and the heat of vaporization. The formula Q = mcΔT can be used to find the heat energy needed, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
To answer this, it is needed to convert one of the temperatures to the same scale as the other. To convert oC to oF, the formula is: F = 9 x C / 5 + 32 So 12oC in Fahrenheit is: F = 9 x 12 / 5 + 32 = 53.6 12oF is less than 53.6oF = 12oC. So 12oF is colder than 12oC.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
If its in Celsius then another 13 degrees are needed because water boils at 100 degrees Celsius
8.200 J
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
because I like cheese