Wiki User
∙ 7y ago539 calories per gram for heat of vaporization plus 1 cal/gram/degree C
100 degrees C - 80 degrees C = 20 degrees C
(539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
Wiki User
∙ 12y agoTo convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius, you need to calculate the heat energy needed to raise the temperature of water from 80 to 100 degrees Celsius (specific heat capacity of water) and then the heat energy needed for water to steam phase change (latent heat of vaporization of water). The total heat energy required can be calculated using the formula: Q = mcΔT + mL, where Q is the heat energy, m is the mass, c is the specific heat capacity, ΔT is the temperature change, and L is the latent heat of vaporization.
Wiki User
∙ 13y agoUse this formula, then convert.
q( in Joules ) = mass * specific heat * change in temp.
q = (5000 grams)(4.180 J/gC)(100 C - 20 C)
= 1672000 Joules
Now, 4.184 Joules = 1 calorie, so....
1672000 Joules (1 calorie/4.184 Joules)
= 399617.59 calories ( you do significant figures )
Wiki User
∙ 13y agoEnergy = mass x specific heat capacity x change in temperature
The specific heat capacity(the energy required to raise 1 kg of a substance by 1 degree Celsius) of water is around 4200 Joules per kilogram per degree Celsius. The change in temperature is 100- 80 = 20 degrees Celsius.
Energy = 50 x 4200 x 20 = 4.2 x 105 Joules
Wiki User
∙ 8y agoApprox 1132 kiloJoules.
Wiki User
∙ 7y ago117,180,000
Anonymous
117,180,000 j
To answer this, it is needed to convert one of the temperatures to the same scale as the other. To convert oC to oF, the formula is: F = 9 x C / 5 + 32 So 12oC in Fahrenheit is: F = 9 x 12 / 5 + 32 = 53.6 12oF is less than 53.6oF = 12oC. So 12oF is colder than 12oC.
Approx 2940 Joules.
The amount of energy needed to reduce water temperature from 15 degrees to 14 degrees depends on the mass of the water and its specific heat capacity. Typically, it would require a minimal amount of energy to achieve such a small temperature change in a small quantity of water.
Approx. 600 - 800 degrees C / 1,100 - 1,500 degrees F
Yes, ice melts at 0 degrees Celsius (32 degrees Fahrenheit) and boils at 100 degrees Celsius (212 degrees Fahrenheit at sea level). These are the specific temperatures at which the phase transitions occur for water.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
18 degrees Celsius is already in the Celsius scale. There is no conversion needed as Celsius and centigrade are the same.
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
The process involves increasing the temperature of water from 8°C to 100°C and then changing its phase to steam at 100°C. The total heat energy required can be calculated using the specific heat capacity of water and the heat of vaporization. The formula Q = mcΔT can be used to find the heat energy needed, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
To answer this, it is needed to convert one of the temperatures to the same scale as the other. To convert oC to oF, the formula is: F = 9 x C / 5 + 32 So 12oC in Fahrenheit is: F = 9 x 12 / 5 + 32 = 53.6 12oF is less than 53.6oF = 12oC. So 12oF is colder than 12oC.
Specific heat capacity tells you how much stuff energy can store. specific heat capacity is the amount of energy needed to raise the temperature of 1kg of a substance by 1 degrees celsius. water has a specific heat capacity of 4200 J/kg degrees celsius.
Water boils at 100 degrees Celsius, so 87 degrees is 13 degrees away from boiling.
True. A calorie is defined as the amount of heat energy needed to raise the temperature of 1 gram of water by 1 degree Celsius.
8.200 J
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
its not needed as it is quite easy to convert Celsius to the Kelvin temperature scale, witch parralels the Celsius scale. subtract 273.15 from celcius to get to kelvin, and 0 is absolute zero on the kelvin scale.