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How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?
To bring the ice block to 0 degrees Celsius, you would need 150,000 Joules (Q = mcΔT). To melt the ice at 0 degrees Celsius, you would need 3,375,000 Joules (Q = mLf). Heating the water from 0 to 100 degrees Celsius would require 1,500,000 Joules (Q = mcΔT). Turning the water to steam at 100 degrees Celsius would need 10,500,000 Joules (Q = mLv). Finally, heating the steam to 120 degrees Celsius would require 600,000 Joules (Q = mcΔT). In total, you would need 15,125,000 Joules of heat energy.
How much heat energy is needed to convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius?
539 calories per gram for heat of vaporization plus 1 cal/gram/degree C 100 degrees C - 80 degrees C = 20 degrees C (539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
What is correct 4.184 or 4.1868 joules per gram for every change in temperature 1 degree centigrade specific heat of water?
The correct value for the specific heat of water is 4.1868 joules per gram per degree Celsius. This means that it takes 4.1868 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How many joules are needed to change 219.70 g of water at 72.7 C to steam at 100 C?
This value is 22,418 kJ.
Why steam is more dangerous than boiling water?
steam scalds are more serious than boiling water scalds because steam when condenses onto the more cooler skin, it loses latent heat of vaporization (to become water at 100 degrees Celsius) also it loses thermal capacity to become equal to the temperature of the skin (37 degrees Celsius). boiling water loses only thermal capacity as it cools down to 37 degrees Celsius from 100 degree Celsius.
How much heat energy would be required to bring a 15 kg block of ice from -20 degrees Celsius to steam at 120 degrees Celsius?
To bring the ice block to 0 degrees Celsius, you would need 150,000 Joules (Q = mcΔT). To melt the ice at 0 degrees Celsius, you would need 3,375,000 Joules (Q = mLf). Heating the water from 0 to 100 degrees Celsius would require 1,500,000 Joules (Q = mcΔT). Turning the water to steam at 100 degrees Celsius would need 10,500,000 Joules (Q = mLv). Finally, heating the steam to 120 degrees Celsius would require 600,000 Joules (Q = mcΔT). In total, you would need 15,125,000 Joules of heat energy.
How much heat is released when 1000g of steam at 100 degrees Celsius condenses?
When steam at 100 degrees Celsius condenses, it releases 2260 Joules of energy per gram. Therefore, for 1000g of steam, the heat released would be 2,260,000 Joules (2260 J/g * 1000 g).
What is the specific heat capacity of steam 100 degrees Celsius?
The specific heat capacity of steam at 100 degrees Celsius is approximately 2.08 J/g°C. This means it takes 2.08 joules of energy to raise the temperature of 1 gram of steam by 1 degree Celsius at that temperature.
How much heat energy will be required to lower the temperature of 2.67kg of steam from 282 degrees Celsius to 105 degrees Celsius?
You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.
How much heat is released when 12.4 g of steam at 100 degrees celsius condenses to water at 100 degrees celsius?
The latent heat of condensation of steam is 2260 Joules per gram (539.3 cals/g). So the amount of heat released by 12.4 g = 12.4*2260 Joules = 28,024 Joules or 6687 cals.
How many joules of energy are needed to heat 25.0 grams of steam from 100.0 degrees Celsius to 29.25 degrees Celsius?
Use this formula. q(in Joules) = Mass * specific heat * change in temperature I will use specific heat of water at 25 C. You can look up specific heat of steam. You say " heat to " so I assume you have final and initial heat backwards. q = 25.0 grams H2O * 4.180 J/gC * (100.0 C - 29.25 C ) q = 7393 Joules
How much heat energy is needed to convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius?
539 calories per gram for heat of vaporization plus 1 cal/gram/degree C 100 degrees C - 80 degrees C = 20 degrees C (539 calories + 20 calories) X 50 kg X 1000 gm/kg = 27950000 cal = 27,950 kcal
How many calories are needed to vaporize 1 gram of boiling water at 100 degrees?
To vaporize 1 gram of boiling water at 100 degrees Celsius, it would require approximately 2260 joules, which is equivalent to about 0.54 calories. This energy is needed to break the intermolecular bonds holding water molecules together, allowing them to escape into the gas phase.
What has the more heat energy at 100 degrees Celsius water or steam?
steam. It has to go through a phase change, which takes additional energy to get there.
What is correct 4.184 or 4.1868 joules per gram for every change in temperature 1 degree centigrade specific heat of water?
The correct value for the specific heat of water is 4.1868 joules per gram per degree Celsius. This means that it takes 4.1868 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Why would Steam at 100 degree celsius burn worse than that of liquid water AT the same temperature?
Steam at 100 degrees Celsius contains more heat energy compared to liquid water at the same temperature. When steam comes into contact with skin, it releases this extra heat quickly, causing more severe burns compared to liquid water of the same temperature.
How many calories are needed to convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius?
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
