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How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
Wiki User
∙ 13y ago
q (amt of heat) = mass * specific heat * temp. difference
The specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oC
q = (105 grams)*(1.00 cal/goC)*(40oC)
= 4,200 calories
Wiki User
∙ 13y ago
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How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How much heat energy is required to change a block of ice with a mass of 55.6 grams at -11.9 degrees Celsius to steam at 123 degree Celsius?
For one gram of ice, it takes 11.9 calories to change the temperature to 0°, 80 calories to melt the ice, 100 calories to raise the water temperature to 100°, 540 calories to change the water to steam, and 23 calories to raise the steam temperature to 123°. That's a total of (11.9 + 80 + 100 + 540 + 23) calories or 754.9 calories. So to do the same to 55.6 grams of ice requires 55.6 times as much heat. 754.9 calories times 55.6 equals approximately 41972 calories (about 42 kilocalories).
How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?
Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------
How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
How much heat is required to vaporize 10 pound ice?
If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams Q = 80(4540) + 1(100 - 0)(4540) + 540(4540) Q = 720(4540) = 3,268,800 calories
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
How much heat is required to raise the temperature of 250 grams of water from 10 degrees to 85 degrees celsius?
The amount of heat required can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass of water (250 grams), c is the specific heat capacity of water (4.18 J/g°C), and ΔT is the change in temperature (85°C - 10°C = 75°C). Plugging in the values, the heat required is approximately 78,750 Joules or 78.75 kJ.
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How many calories are required to raise 8 grams of water 7 degrees Celsius?
The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How much heat energy is required to change a block of ice with a mass of 55.6 grams at -11.9 degrees Celsius to steam at 123 degree Celsius?
For one gram of ice, it takes 11.9 calories to change the temperature to 0°, 80 calories to melt the ice, 100 calories to raise the water temperature to 100°, 540 calories to change the water to steam, and 23 calories to raise the steam temperature to 123°. That's a total of (11.9 + 80 + 100 + 540 + 23) calories or 754.9 calories. So to do the same to 55.6 grams of ice requires 55.6 times as much heat. 754.9 calories times 55.6 equals approximately 41972 calories (about 42 kilocalories).
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.
How many calories would be needed to melt 10 grams of ice at 0 degrees C?
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
How many grams of water vapor are required to saturate a kilogram of air at a temperature of -20 degrees Celsius?
At -20 degrees Celsius, the saturation vapor pressure of water is about 2.2 millibars. Therefore, to saturate a kilogram of air at this temperature, you would need about 2.2 grams of water vapor.
How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?
Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------
How much energy is required to raise 21kg of water by 2 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
