Wiki User
∙ 11y agoThe phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
Wiki User
∙ 14y agoWiki User
∙ 11y agoThe offspring of a homozygous dominant and homozygous recessive cross will be heterozygous. This means that they will have one of each allele, and will have the phenotype of the dominant allele.
For example, if B leads to black fur and b leads to white fur:
The cross BB (black) X bb (white) will result in Bb (black) offspring.
Dakota Mullins
What percent of offspring have…
a homozygous dominant genotype?
All the offspring will be heterozygous for that trait, as they will inherit one dominant allele and one recessive allele from their parents.
Wiki User
∙ 14y agotHE 9:3:3:1 only applies to dihybrid cross: a monohybrid cross between two heterozygotes gives a 3:1 ratio
Wiki User
∙ 11y agohomozygou because both are dominate traits
Wiki User
∙ 13y agoBe recessive
In a test cross, one individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. The genotype of the individual with the dominant phenotype can then be inferred based on the phenotypic ratios of the offspring.
Out of the 240 offspring, approximately 60 would be homozygous (25% of 240). This is because when two heterozygous plants are crossed (Aa x Aa), the Punnett square shows that 25% of the offspring will be homozygous dominant (AA), 50% will be heterozygous (Aa), and 25% will be homozygous recessive (aa).
The term "parental genotypes" can describe the genotypes of the P generation in a genetics experiment. These genotypes serve as the initial individuals crossed to produce offspring with specific traits of interest.
The ratio produced would be 1:1 for heterozygous (Tt) offspring to homozygous recessive (tt) offspring. This is because the parent with genotype Tt will pass on one dominant allele (T) and one recessive allele (t) to its offspring, resulting in a 50% chance of either genotype in the offspring.
Not if either trait is dominant. Let us say tall is dominant ( I think it is ) and short is recessive. T = tall, and s = short. TT X ss will give heterozygous tall plants. Ts
100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.
In a test cross, one individual with a dominant phenotype but unknown genotype is crossed with a homozygous recessive individual. The genotype of the individual with the dominant phenotype can then be inferred based on the phenotypic ratios of the offspring.
A dominant trait will appear in offspring that inherits at least one copy of the dominant allele from either parent. If an individual has two different alleles for a trait (one dominant and one recessive), the dominant trait will be expressed.
The offspring will all inherit one copy of the dominant allele (from the heterozygous parent) and one copy of the recessive allele (from the homozygous recessive parent). This results in all offspring being heterozygous for the trait.
Out of the 240 offspring, approximately 60 would be homozygous (25% of 240). This is because when two heterozygous plants are crossed (Aa x Aa), the Punnett square shows that 25% of the offspring will be homozygous dominant (AA), 50% will be heterozygous (Aa), and 25% will be homozygous recessive (aa).
100%
The homozygous recessive individual is used in a test cross to determine the genotype of an individual with a dominant phenotype but unknown genotype. When crossed with a homozygous recessive individual, if any offspring display the recessive trait, it indicates that the unknown individual is heterozygous for that trait.
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
The offspring would most likely have a 50% chance of inheriting the heterozygous trait and a 50% chance of inheriting the homozygous recessive trait.
homozygous recessive
Because Mendel crossed two pure-breeding plants. One being homozygous dominant and one being homozygous recessive. All of the progeny ended up being heterozygous, causing them to take on the dominant phenotype and look like the homozygous dominant parent.
If two homozygous plants with contrasting traits are crossed, the expected genotypes for the offspring will be heterozygous. The dominant trait would be expressed, but they'd be carriers for the recessive trait.