FALSE!
The object's acceleration is equal to the change in velocity divided by the time taken. The initial velocity is 30 miles per second, and the final velocity is 0 miles per second. The change in velocity is 30 miles per second. Therefore, the acceleration is 30 miles per second divided by 5 seconds, which is 6 miles per second squared.
If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.
Find out the time using speed and acceleration, (time=speed/acceleration) and then use it to find out uniform velocity. From that find out uniform acceleration. (as uniform acceleration is equal changes of velocity over equal intervals of time)
'v' generally refers to final velocity 'u' generally refers to initial velocity (because not everything starts from a motionless state, where 'u' would equal zero) It is better to annotate initial velocity as v0 (v-sub-zero or simply v-zero).
Yes, the rate of change of velocity is equal to acceleration. This means that if an object's velocity is changing, it is experiencing acceleration, either by speeding up, slowing down, or changing direction.
No, It is the average velocity.
A change in velocity can be effected only by acceleration. Therefore, if the acceleration is zero, there is no change, so final velocity equals initial velocity.
Average Acceleration can be verbally defined as the change in velocity in a certain change in time... More simply put: Average Acceleration = (Final Velocity - Initial Velocity) / (Final Time - Initial Time)
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.
It's equal to the change in velocity (final velocity - initial velocity).
That's the velocity at any time.
Velocity is equal to distance traveled divided by the time it took to travel. v = d / t Velocity also equals the initial velocity plus the acceleration times time. v = v1 + a(t)
It doesn't "affect" it. Acceleration is DEFINED as (delta v) / (delta t), or change in velocity divided by the time elapsed; so whenever you have a delta-v, you'll have an acceleration (the amount of which also depends on the time elapsed).
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
Without time given, it is not possible to calculate the initial speed. The initial speed can be determined only if you have the time taken to reach a certain point from rest, along with the distance traveled or acceleration information. The formula to calculate initial speed is v = u + at, where v is the final velocity, u is the initial velocity, a is acceleration, and t is time.
The formula for acceleration can be rewritten as a = Δv / Δt, where acceleration (a) is equal to the change in velocity (Δv) divided by the change in time (Δt).