logically no because if it is a yes, then the light reaching the detector is greater than the light which was produced by the machine in the first place. But you may get transmittance greater than 100 because some parameters of your experiment may not be right.
IR spectra seldom show regions at 100% transmittance because most molecules absorb some infrared radiation due to their unique bond vibrations. Even if there are no absorptions in a particular region, factors like impurities, instrument noise, or scattering can lead to a lack of complete transmittance.
In IR spectroscopy, transmittance is often plotted because it provides a direct measurement of how much infrared light passes through a sample compared to the incident light. This approach aligns with the common practice of measuring the intensity of transmitted light, making it easier to visualize and interpret spectra. Additionally, transmittance values range from 0 to 100%, which can be more intuitive for understanding the sample's interaction with light, whereas absorbance values can vary widely and may not be as straightforward to interpret.
Zeroing the spectrophotometer on 0 and 100% transmittance ensures that the instrument is properly calibrated and accounts for potential variations in the blank solution that might affect the absorbance readings. This calibration process helps to provide more accurate and reliable absorbance measurements for the samples being analyzed.
The percent efficiency would be calculated by dividing the useful output by the total input energy and multiplying by 100. In this case, the useful output is 6W (light energy produced) and the total input is 60W (electricity consumed). Therefore, the efficiency would be (6/60) * 100 = 10%.
No, LED lights typically have a higher lumen efficiency than traditional incandescent bulbs, but they are not 100 percent efficient. LED lights can convert more of the electricity they consume into visible light, resulting in higher lumen output for the same amount of power. However, some energy is still lost as heat.
Absorbance = -log (percent transmittance/100)
IR spectra seldom show regions at 100% transmittance because most molecules absorb some infrared radiation due to their unique bond vibrations. Even if there are no absorptions in a particular region, factors like impurities, instrument noise, or scattering can lead to a lack of complete transmittance.
47 percent out of 100 percent is 47 percent (0.47 x 100 percent = 47 percent). More clearly, 47 % / 100 % = 47 / 100 = 0.47
22%= 100% - 78%= 22%
14% more
Yes, it can.
100% alcohol is more effective because of the more alcohol concentration in the drink.
Glass, 100 percent pure water, and light.
No, an amount cannot be decreased by more than 100 percent. To decrease by more than 100 percent would mean that the amount is actually going into the negative values, which is not possible in most contexts. A decrease of 100 percent means that the amount is reduced to zero.
a percent yield will be above 100 if the product used are wet or more likely impure.
Yes. Fifty percent would be half of 100, and eighty-three percent is greater than fifty percent.
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