Wiki User
∙ 15y agoEight 8 Dont have Brown eyes or brown hair because it says 12 have both brown hair and brown eyes so subtract that by 20 and you get eight 8
Wiki User
∙ 15y agoThere are 4 students who do not have brown hair or brown eyes. This can be calculated by adding the students with brown hair (15) and brown eyes (16), then subtracting the students with both (12) from that total. This gives us 19 students with either brown hair or brown eyes. Subtracting this from the total number of students (20) gives us the number of students with neither brown hair nor brown eyes.
Wiki User
∙ 10y ago5
Yes, it is possible for a blue-eyed male and a brown-eyed female to have a brown-eyed child. Eye color is a polygenic trait, meaning it is influenced by multiple genes. Both parents can carry genes for brown eyes, and if those genes are passed on to the child, they can have brown eyes even if neither parent has brown eyes.
neither
Blue eyes are a recessive trait. If at least one of the parents had a blue/hazel eyes with a mixture of blue and brown, then the couple's offspring could have brown eyes. If both parents had solid blue eyes, neither would have the dominant brown gene to pass to the baby, and it would have blue eyes, regardless of the grandmother's eye color.
baking powder
When an allele is neither dominant nor recessive, it means that both alleles equally influence the trait. This is known as codominance, where both alleles are expressed in the phenotype of the individual.
55 students speak English, 85 students speak Telugu, and 30 students speak neither. To find out how many students speak both English and Telugu, we can use the formula: Total = English + Telugu - Both + Neither. Plugging in the values: 150 = 55 + 85 - Both + 30. Solving for Both, we get: Both = 10 students.
Since 6 students like neither, 21 students like math, and 2 students like physics, then only one student likes both math and physics (30 - 29).
600 in the class. 222 brought both pens and pencils so all the rest did not bring both ie 378 (=600-222) did not bring both. Some brought pens, some pens and some neither.
the answer would be 4 students
27
14 students take neither Spanish nor French.
my notes from my class say maladaptive....
The field for liking both is a maximum of 93 -30 ie 63. There are 83 "likers" in total so 20 must like both, while 22 like maths, 21 like English and 30 like neither, giving the required 93 total.
Neither, sponges have their own phylum separate from both of those, called Porifera ('pore carriers').
formative assessment, as it is used to gauge students' understanding of the material and provide feedback to both students and teachers on their progress.
eat the a guys pingpong "balls"
Here are 10 students getting honors credits in a class, and they make up 20% of the class. How do we find the number of students in the class? Let's look. We have a class, and 20% of the class are getting honors credit, and that turns out to be 10 students. Now we can generate a formula that we can use to discover our answer. Let's assign letters to the things we know or are finding out. Nclass = number of students in the class. Nhonors = number of honors students in the class. And Nhonors = 10 students. Nclass x 20% = 10 students 20% = 20/100ths (because % = hundredths) or 0.20 or just 0.2 for simplicity. Nclass x .2 = 10 students Now divide both sides by .2 so the .2 will cancel out (or drop out) on the left side of the equation and we'll have isolated the answer we are looking for, which is Nclass. Nclass = 10 students divided by .2 Nclass = 10/.2 students = 50 students There are 50 students in the class. As .2 equals 2/10 or 1/5, we can find 1/5th of 50 just by thinking about it to check our work. And 1/5th of 50 equals 10, which is in agreement with the information we were given in the problem.