IsaiahDavisgp9002
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
Wiki User
∙ 9y agoDensity = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
The answer depends on what characteristic of the gold nugget you wish to measure: its mass, weight, volume, density, temperature, electrical conductivity, etc.
The formula to calculate density is: Density = mass / volume. You simply divide the mass of an object by its volume to find its density. Density is a measure of how much mass is contained in a given volume.
To find the density of an object, you need to measure its mass and volume. Then, divide the mass by the volume to calculate the density. The formula for density is density = mass/volume.
To convert volume to mass, you need the density of the substance. Multiply the volume by the density to get the mass using the formula: mass = volume x density. The units of volume and density must be compatible for accurate conversion.
Since the density of gold is higher than that of iron pyrite, the gold nugget will have a smaller volume than the iron pyrite nugget. This is because for two materials with the same mass, the denser one will occupy less space.
Since the mass of both nuggets is the same, the volume of the gold nugget will be smaller than the volume of the iron pyrite nugget. Gold is denser than iron pyrite, so it requires less volume to achieve the same mass.
To determine whether the nugget is real gold or fool's gold, you can calculate its density. The density of gold is 19.32 g/cm3, while the density of fool's gold (iron pyrite) is about 5 g/cm3. Based on the displacement of water and the mass provided, calculate the density of the nugget using the formula: density = mass/volume. Compare the calculated density to the known densities of gold and fool's gold to identify the material.
The density of pyrite is about 5 g/cm³. To find the mass of the pyrite, you can use the formula: mass = density x volume. Therefore, in this case, the mass of the pyrite would be 50 grams.
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
With the information given, the density of your nugget is about 19.29 g/cc. The density of gold is given as about 19.3 g/cc, so your nugget fits the density requirements for it to be a gold nugget.
The density of the gold nugget is 19.3 g/cm^3. This was calculated by dividing the mass (965 g) by the volume (50 cm^3).
Yes, the density of gold is known (19.32 g/cm^3). By using the formula for density (density = mass/volume), you can calculate the expected volume the gold nugget should displace based on its mass. If the calculated volume matches closely with the measured volume, it is likely the nugget is made of gold.
Pyrite has a density of 4.8-5g/cm3 mass = density x volume = (4.8-5)g/cm3 x 10 cm3 = 48 to 50 grams.
Density = Mass/Volume = 57.2g/11 cm3 = 5.2 gcm-3
Assuming the gold nugget is solid and pure (unlikely in real life!) The volume of the nugget is 77.0 - 50.0 mL = 27.0 mL So density = mass/volume = 521/27.0 = 19.3 g per mL.
The answer depends on what characteristic of the gold nugget you wish to measure: its mass, weight, volume, density, temperature, electrical conductivity, etc.