27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
2g/cm3
The idea is to divide the mass by the volume.
This density is 0,8 g/cm3.
The density is (the mass, in grams)/100 grams per cm3 .
The density of aluminum is 2.70 g/cm3. To find the density of 100 cm3 of aluminum with a mass of 250g, divide the mass by the volume: 250g / 100 cm3 = 2.50 g/cm3. The density of the aluminum sample is 2.50 g/cm3.
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
In order to determine the mass of the water sample, you would need to know the density of water. The density of water is approximately 1 g/cm3. Therefore, the mass of a 20 cm3 sample of water would be 20 grams (20 cm3 * 1 g/cm3 = 20 grams).
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
the density of pyrite or fool's gold is 5.01g/cm3
2g/cm3
To determine whether the nugget is real gold or fool's gold, you can calculate its density. The density of gold is 19.32 g/cm3, while the density of fool's gold (iron pyrite) is about 5 g/cm3. Based on the displacement of water and the mass provided, calculate the density of the nugget using the formula: density = mass/volume. Compare the calculated density to the known densities of gold and fool's gold to identify the material.
The density of the ore sample is 1.97 g/cm3. This value is calculated by dividing the mass of the ore (57 g) by its volume (29 cm3).
density = mass/volume = 250g/45cm3 = 5.6g/cm3 (rounded to 2 sig figs)
The mass of the nickel sample is 39.2 g (9.8 g/cm3 * 4 cm3), and the mass of the lead sample is 45.2 g (11.3 g/cm3 * 4 cm3).
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