Pyrite has a density of 4.8-5g/cm3
mass = density x volume
= (4.8-5)g/cm3 x 10 cm3
= 48 to 50 grams.
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
2g/cm3
The idea is to divide the mass by the volume.
This density is 0,8 g/cm3.
volume =mass/ density volume = 55.932/8.92 = 6.27 cm3
The density of aluminum is 2.70 g/cm3. To find the density of 100 cm3 of aluminum with a mass of 250g, divide the mass by the volume: 250g / 100 cm3 = 2.50 g/cm3. The density of the aluminum sample is 2.50 g/cm3.
27.3 g is the mass of an aluminum sample with a volume of 10.0 cm3.
In order to determine the mass of the water sample, you would need to know the density of water. The density of water is approximately 1 g/cm3. Therefore, the mass of a 20 cm3 sample of water would be 20 grams (20 cm3 * 1 g/cm3 = 20 grams).
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
Iron pyrite (FeS2) has a density of 4.8 to 5.0 grams per cm3. A piece of volume 40 cm3 would, therefore have a mass of volume*density = 192 to 200 grams.
the density of pyrite or fool's gold is 5.01g/cm3
2g/cm3
Density = mass/volume, So, Density = 57g/29cm3 = 2.0g/cm3* The number on the calculator is 1.965517241, which is rounded to 2.0 because of significant figures.
density=g/cm3 The density of Gold is 19.3g/cm3 The density of Fool's Gold (pyrite) is 5g/cm3 The question is slightly ambiguous as first written so two calculations are given: # 100/15= 6.666g/cm3 So this nugget is possibly pyrite and not gold. 100/5= 20g/cm3 So this nugget is possibly gold.
density = mass/volume = 250g/45cm3 = 5.6g/cm3 (rounded to 2 sig figs)
The mass of the nickel sample is 39.2 g (9.8 g/cm3 * 4 cm3), and the mass of the lead sample is 45.2 g (11.3 g/cm3 * 4 cm3).
Start by writing the formula that you probably know for density D=m/V Now plug in the data that you have: 2.336 g/cm3 = m/350 cm3 so, m = 350 x 2.336 = 817.6 g