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The half-life of fluorine-20 is 11.4 seconds After seconds 1 4 of the original amount of fluorine-20 will remain?
Limeboy18
25
Wiki User
∙ 11y ago
After 11.4 seconds, half of the original amount of fluorine-20 will remain. Therefore, after 11.4 seconds, 25% (1/4) of the original amount will remain.
Wiki User
∙ 10y agoSo it has gone through 2 hald lives: 1/2 x 1/2, so 11.4+11.4 is 22.8 seconds later.
Wiki User
∙ 13y ago22.8
Wiki User
∙ 14y ago1/16
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The half-life of fluorine-20 is 114 seconds After 14 seconds how much of the original amount of fluorine-20 will remain?
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
An artifact is found that some are claiming is 30000 years old 3.1 percent of the original carbon14 is present The halflife of carbon14 is 5730 year?
To determine the age of the artifact, you can use the formula for exponential decay of radioactive elements: (N = N_0 \times (1/2)^{t/T}), where N is the final amount (3.1% of the original), N0 is the initial amount (100%), t is the time passed, and T is the half-life (5730 years). By substituting the values, you can solve for t, which will give you the age of the artifact.
Can you use carbon dating to find out how old something is around 40 years old or newer?
Carbon dating is not usually used for samples younger than 50,000 years because the amount of radioactive carbon-14 left in such recent samples is too small to accurately measure. For objects around 40 years old or newer, other dating methods like tree-ring dating or historical records are more appropriate.
What is the half life of uranium 238 if 85.719 percent of any given amount remains after 1 billion years?
The half-life of uranium-238 is approximately 4.47 billion years. If 85.719% of the original amount remains after 1 billion years, then the remaining 14.281% would have decayed in that time period.
After how many days 1-4 of the original amount of gold 198 will remain?
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
The half life of fluorine-20 is 11.4 seconds After seconds 1'4 of the original amount of fluorine-20 will remain?
22.8 seconds
How do you determine the half life of a radioactive substance that has changed through radioactive decay After 40 days the original substance left is is one sixteenth of the original amount?
To determine the half-life of the substance, you can use the fact that after one half-life, the substance will be reduced to half of its original amount. In this case, after 40 days, the substance is reduced to one sixteenth of its original amount, which represents 4 half-lives (since 1/2^4 = 1/16). Thus, each half-life of this substance is 10 days.
The half-life of fluorine-20 is 114 seconds After 14 seconds how much of the original amount of fluorine-20 will remain?
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
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kze gWapo aQo
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You multiply the amount of minutes by the amount of seconds in a minute. 27*60 The answer is 1620
How many minutes are there in 28000 seconds?
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