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After years 14 of the original amount of colbalt 60 will remain?
Cobalt-60 has a half-life of approximately 5.27 years, meaning that after this period, half of the original amount will have decayed. After 14 years, which is about 2.65 half-lives, the remaining amount can be calculated using the formula: remaining amount = original amount × (1/2)^(time/half-life). Therefore, after 14 years, approximately 1/6 of the original amount of cobalt-60 will remain.
What fraction of a radioactive nuclei remain after p half lives?
The remainder is 2-p or 0.5p of the original amount.
A 200 gram sample having a half- life of 12 seconds would have how much remaining after 36 seconds?
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
What fraction of a radium sample will remain after 3240?
The answer depends on 3240 WHAT: seconds, days, years?
If the base of a triangle is doubled how does the perimeter change?
If the base of a triangle is doubled while the other sides remain unchanged, the perimeter of the triangle will increase by the amount equal to the original base length. Specifically, if the original base is ( b ) and the other two sides are ( a ) and ( c ), the new perimeter becomes ( (2b + a + c) ), resulting in an increase of ( b ). Thus, the total perimeter becomes the original perimeter plus the original base length.
The half-life of fluorine-20 is 11.4 seconds After seconds 1 4 of the original amount of fluorine-20 will remain?
25
The half-life of fluorine-20 is 114 seconds After 14 seconds how much of the original amount of fluorine-20 will remain?
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
After how many days 1-4 of the original amount of gold 198 will remain?
After 4 days, only 1/16 of the original amount of gold (198/16 = 12.375) will remain.
The half-life of cobalt-60 is 5.3 years After years 1 4 of the original amount of cobalt-60 will remain?
After 1 year, 50% of the original amount of cobalt-60 will remain. This means that 50% will decay and 50% will be left. After 4 years, 6.25% of the original amount (50% of 50%) of cobalt-60 will remain.
After years 14 of the original amount of colbalt 60 will remain?
Cobalt-60 has a half-life of approximately 5.27 years, meaning that after this period, half of the original amount will have decayed. After 14 years, which is about 2.65 half-lives, the remaining amount can be calculated using the formula: remaining amount = original amount × (1/2)^(time/half-life). Therefore, after 14 years, approximately 1/6 of the original amount of cobalt-60 will remain.
The half-life of gold198 is 27 days After days 14 of the original amount of gold198 will remain?
5.4
What fraction of a radioactive nuclei remain after p half lives?
The remainder is 2-p or 0.5p of the original amount.
How much Uranium 235 would remain after 4 half lives?
After one half-life, half of the original amount of Uranium-235 would remain. After four half-lives, only ( \frac{1}{2^4} ) or ( \frac{1}{16} ) of the original amount would be left. Therefore, if you started with 100 grams of Uranium-235, 6.25 grams would remain after four half-lives.
How many grams are left after sixty seconds of rhodium one hundred six if the half life is thirty seconds?
1/4 of the amount that was originally there will remain. Note that the rest doesn't simply evaporate, it will decay into something else.
How much thorium-234 will remain after 2 half lives?
After 2 half-lives, 25% of the original amount of thorium-234 will remain. This is because half of the substance decays in each half-life period.
The half life of cobalt 60 is 5.3 years After years 14 of the original amount of cobalt 60 will remain?
After 14 years, 1/16th of the original amount of cobalt-60 will remain, because 14 years is equivalent to 2.64 half-lives of cobalt-60 (14 years / 5.3 years/half-life). Each half-life reduces the amount of cobalt-60 by half, so after 2.64 half-lives, the original amount will be reduced to 1/2^2.64 which is approximately 1/16th.
How do you get skinny in 5 seconds?
There is no possible way to 'get skinny' in five seconds and remain healthy.
