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twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).

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1mo ago

Let the width be x feet.

Then, the length would be (x+7) feet.

Given that decreasing the length by 3 feet and increasing the width by 2 feet gives a perimeter of 32 feet, you can set up the equation 2( (x+7) - 3 + x + 2) = 32 to find the original width x and length (x+7).

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Q: The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?
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