It means acceleration.
It means that either the distance is measured from the starting-line and the object is moving forward, or else the distance is measured from the finish-line and the object is moving backwards, because the distance is growing as time goes on. If the upward sloping diagonal line is straight, it means the speed is constant. (not velocity)
An downward sloping diagonal line on a position vs. time graph indicates constant negative acceleration or deceleration. This means that the object is moving in the negative direction and slowing down over time.
A sudden change in slope or discontinuity in the graph would indicate a phase change taking place. This can be seen as a sharp point or step-like feature in the graph.
The area between the graph and the x-axis is the distance moved. If the velocity is constant the v vs t graph is a straight horizontal line. The shape of the area under the graph is a rectangle. For constant velocity, distance = V * time. Time is the x-axis and velocity is the y-axis. If the object is accelerating, the velocity is increasing at a constant rate. The graph is a line whose slope equals the acceleration. The shape of the graph is a triangle. The area under the graph is ½ * base * height. The base is time, and the height is the velocity. If the initial velocity is 0, the average velocity is final velocity ÷ 2. Distance = average velocity * time. Distance = (final velocity ÷ 2) * time, time is on the x-axis, and velocity is on the y-axis. (final velocity ÷ 2) * time = ½ time * final velocity ...½ base * height = ½ time * final velocity Area under graph = distance moved Most velocity graphs are horizontal lines or sloping lines.
Concave up. "Acceleration is increasing with time" tells us that the derivative of acceleration is positive. Since acceleration is the derivative of velocity, this means that the second derivative of velocity is positive. By definition, having a non-negative second derivative means that velocity is concave up.
It means that either the distance is measured from the starting-line and the object is moving forward, or else the distance is measured from the finish-line and the object is moving backwards, because the distance is growing as time goes on. If the upward sloping diagonal line is straight, it means the speed is constant. (not velocity)
This means your velocity is decreasing with time, or in other words, the object is slowing down.
The graph would be a straight line with a positive slope, indicating a constant displacement over time.
False. A horizontal line on a velocity vs. time graph indicates constant velocity, not constant acceleration. Positive acceleration would be represented by a diagonal line sloping upwards on a velocity vs. time graph.
An upward sloping straight line.
A straight line sloping upwards on a position-time graph indicates that the object is moving with a constant positive velocity. The slope of the line represents the velocity of the object.
Acceleration , which is change of velocity over time.
An upward sloping straight line indicates that the object being studied is moving away from the origin and that the component of its velocity in the radial direction is a constant. A downward sloping line indicates it is moving towards the origin. However, neither line says anything about the transverse component of its motion.
An Upward Sloping Straight Line. <3
If you want the graph to show the acceleration of the ball against time, then the graph is a horizontal line. If you want the graph to show the velocity of the ball against time, then the graph is a straight line sloping downward. If you want the graph to show the height of the ball against time, then the graph is a parabola that opens downward.
Deceleration can be symbolized as a negative value in an equation or graph, indicating a decrease in speed or velocity. It can also be represented by a downward sloping line on a velocity-time graph, showing a decrease in velocity over time.
The velocity-time graph of an object thrown vertically upward will have a parabolic shape. The velocity will decrease from the initial positive value until reaching zero at the peak of its motion, then become negative as it falls back down. The velocity-time graph will be symmetric about the point where the object reaches its highest point.