This equation shows that the energy of a photon is inversely proportional to its wavelength.
E = Energy.
h = The Planck constant. Think of it as a tiny, discrete packet of energy for most purposes.
Nu (looks like v) = Spatial frequency of a wave.
Nu is equal to 1/Wavelength (inversely proportional). The way to think of this is that wavelength is how many meters long the wave is. Meanwhile, Nu is how many waves you can fit into a meter.
Eg: If the wave is half a meter long, you can fit 2 waves into a metre. (Nu = 1/0.5 = 2)
If Nu is large, it means we can fit a lot of waves into our unit length (remember, big Nu = small wavelength and vice versa). What does this mean for our equation? It means when Nu is high, we have high energy (remember h is a positive constant). When Nu is low, we have low energy.
In English, this means photons with smaller wavelength have higher energy than photons with larger wavelengths. This universally true, and extremely important.
For further reading, try searching for "Electromagnetic spectrum".
The energy of the photons released during an atomic emission spectrum can be calculated using the equation (E = h \nu), where (E) is the energy of the photon, (h) is Planck's constant ((6.626 \times 10^{-34} , \text{J s})), and (\nu) is the frequency of the emitted light. The frequency can be related to the wavelength ((\lambda)) of the light using the equation (\nu = \frac{c}{\lambda}), where (c) is the speed of light ((3.00 \times 10^8 , \text{m/s})). By measuring the wavelength of the emitted light, you can determine its frequency and subsequently calculate the energy of the photons.
Radon-198 does not decay via beta decay. It is thought to decay by alpha decay, but that is not certain. The equation would be ... 86198Rn -> (Alpha, T1/2 = 86 ms) -> 84194Po + 24He2+
The nuclear decay equation for carbon-11 is: [ _{6}^{11}C \rightarrow {7}^{11}N + e^{+} + \nu{e} ] where ({6}^{11}C) is the carbon-11 nucleus, ({7}^{11}N) is the nitrogen-11 nucleus, (e^{+}) is a positron (positive electron), and ( \nu_{e} ) is an electron neutrino.
When an electron drops to a lower energy level in an atom, it releases energy in the form of a photon. The energy of the emitted photon corresponds to the difference in energy between the two levels, calculated using the equation (E = h \nu), where (E) is the energy of the photon, (h) is Planck's constant, and (\nu) is the frequency of the emitted light. This energy can also be expressed in terms of wavelength using the equation (E = \frac{hc}{\lambda}), where (c) is the speed of light and (\lambda) is the wavelength. Thus, the energy of the photon released is specific to the transition between the electron's initial and final energy states.
Planck's constant is measured in joule-seconds (J·s). This unit arises from its role in quantum mechanics, where it relates the energy of a photon to its frequency. Specifically, the equation ( E = h \nu ) shows that energy (in joules) is proportional to frequency (in hertz), with Planck's constant as the proportionality factor.
The Dittus-Boelter equation is used to calculate the convective heat transfer coefficient in a fluid flowing inside a tube. It applies to fully developed turbulent flow in the range of Reynolds numbers typically between 3000 and 100,000. The equation is given as Nu = 0.023Re^0.8Pr^0.4, where Nu is the Nusselt number, Re is the Reynolds number, and Pr is the Prandtl number.
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The equation for electromagnetic radiation is E = hν, where E is the energy of a photon, h is Planck's constant, and ν is the frequency of the radiation.
In the equation ( E = h \nu ), ( h ) is known as Planck's constant. It is a fundamental physical constant that relates the energy of a photon to its frequency ( \nu ). Planck's constant has a value of approximately ( 6.626 \times 10^{-34} ) joule-seconds, and it plays a crucial role in quantum mechanics.
35S --> 35Cl + e- 35Cl, stable
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