Wiki User
∙ 13y agoLet t1 and t2 be the times for the two stages.
Then t1 = x/v1
and t2 = x/v2
Total distance = x + x = 2x
Total time = t1 + t2 = x/v1 + x/v2 = x*(1/v1 + 1/v2)
Average velocity = total distance / total time
= 2x divided by x/(1/v1 + 1/v2)
= 2(1/v1 + 1/v2) which is the Harmonic mean of v1 and v2.
Wiki User
∙ 13y agoThe average velocity is the total displacement divided by the total time. Since the person is traveling with a uniform velocity, the total displacement will be the sum of the individual displacements (x) at velocities v1 and v2. Therefore, the average velocity will be the ratio of total displacement to total time taken for the journey.
Average velocity is defined as the change in position of an object divided by the time taken to undergo that change. It gives a measure of how fast an object is moving in a particular direction over a given time interval. Mathematically, it is represented as: average velocity = (final position - initial position) / time.
Acceleration measures the rate of change in velocity. It is defined as the change in velocity per unit of time. Positive acceleration indicates an increase in velocity, while negative acceleration indicates a decrease in velocity.
To calculate distance from a velocity-time graph, you would find the area under the curve, as this represents the displacement or distance traveled. If the graph is above the time axis, calculate the area above the time axis, and if it dips below, calculate the area below the time axis. Summing these two areas will give you the total distance traveled.
Yes, since velocity is speed and direction its average can be zero. For example say a plane flies from point A to point B at 300 mph and turns around to go from B to A at 300 mph; its average velocity is 0 since it is in the same spot as it started ( the velocity vectors cancel) but its average speed is 300 mph.
No, a radio controlled car would not have an average velocity of zero if it moves in a straight line. Average velocity is the total displacement divided by the total time, so as long as the car moves, it will have a non-zero average velocity.
The slope of the ant's displacement vs. time graph The total displacement divided by the time.
The slope of the ant's displacement vs. time graph The total displacement divided by the time.
The slope of the ant's displacement vs. time graph The total displacement divided by the time.
Velocity (or speed) = Distance ÷ Time In this example, speed = 300/6 = 50 kph
No. Average speed is.
No, distance and average velocity are not the same. Distance is the total amount covered by an object irrespective of direction, while average velocity is the displacement of an object divided by the time taken, taking direction into account.
Yes, average velocity and average speed can be the same if an object moves in a straight line without changing direction. Average velocity takes into account both the speed of the object and its direction of motion, while average speed is the total distance traveled divided by the total time taken.
Average velocity equals the average speed if (and only if) the motion is in the same direction. If not, the average speed, being the average of the absolute value of the velocity, will be larger.
1. magnitude of distance covered is equal to the magnitude of displacement. 2. the motion of the object is in a straight line i.e. in a particular direction.
Average velocity is defined as the change in position of an object divided by the time taken to undergo that change. It gives a measure of how fast an object is moving in a particular direction over a given time interval. Mathematically, it is represented as: average velocity = (final position - initial position) / time.
No, distance is not a magnitude of average velocity. Distance is a scalar quantity that measures the total path length traveled without regard to direction, while average velocity is a vector quantity that measures the displacement over a specific time period.
Distance = time * average speed (velocity) Average speed = Distance/time