Divide mass by volume as they are now and get the answer in g/cm3 (pretty standard form).
If you divide 97 by 21.9, you'll get 4.429
If it specifically asks for certain units just multiply or divide your answer through... For example, if you need the your answer in kg/cm3, divide 97 by 21.9 and divide that by 1000.
The density of the ore sample is 97 g / 21.9 cm3 = 4.43 g/cm3.
do you mean 100 ml? most solutions are given in terms of volume not mass. But ...CaCl2 has a molar mass of 111 g The hydrated form also contains 108 g water. This gives a total mass of 219 g for the hydrated form.The solution must contain: 100 g x 5% = 100 x 5/100 = 5g anhydrous CaCl25 / x = 111 / 219solve for x: x = 5(219)/111 = 9.865 g of the hydrate
Depends entirely on the vehicle, if you get 8 mpg, like on a land rover, it going to take lots, if your driving a prius its like 5 gallons.
The weight of radium can vary depending on the specific isotope. For example, the most common isotope, radium-226, has an atomic weight of approximately 226 grams per mole.
200yards x 3ft/1yd x 1meter/3.28ft = 182.93 meters
To determine how many pounds a cubic 3.5 feet container can hold, you need to know the density of the material being filled into the container. Once you have the density of the material in pounds per cubic foot, you can multiply it by 3.5 cubic feet to find out the total weight the container can hold in pounds.
Sturkö's population density is 219 people per square kilometer.
The population density of Landfjärden is 219 people per square kilometer.
The population density of Eersel is 219 people per square kilometer.
Thorium-219 has a half-life of about 1.4 minutes. To calculate the time it takes for a 2kg sample to decay to 15.6g, you would need to use the radioactive decay formula. This would involve determining the number of half-lives it takes for the 2kg sample to decay to 15.6g.
Total mass:Ca = 40 g2 Cl = 2x35.5 =71g6x H2O = 6x18 = 108gTotal mass = 219 g% water (by mass) = 108 g/219 g (x100) = 49.3 % water
The percentage of 78% of 219 = 100*(78% of 219) = 100*(219*78/100) = 219*78 = 17082%The percentage of 78% of 219 = 100*(78% of 219) = 100*(219*78/100) = 219*78 = 17082%The percentage of 78% of 219 = 100*(78% of 219) = 100*(219*78/100) = 219*78 = 17082%The percentage of 78% of 219 = 100*(78% of 219) = 100*(219*78/100) = 219*78 = 17082%
39% of 219= 39% * 219= 0.39 * 219= 85.41
219-g= 219-g
303-219 = 84
219-77 = 142
What should happen is that you are asked to express 219 in some context. 219 what? Bits of work that you did not hand in? 219 mistakes on a single page? 219 marks out of 220 (excellent!) or 219 marks out of 2,000 (pathetic!).
494-219 = 275