5ml of the 1000 ppm solution in 95ml distilled water gives a 500ppm solution
To prepare a 100 ppm KCl solution from a 1000 ppm KCl solution, you would need to dilute the concentrated solution. Take 10 mL of the 1000 ppm KCl solution and add it to a volumetric flask or a similar container. Then, add enough distilled water to reach a final volume of 100 mL. This dilution results in a 100 ppm KCl solution.
To dilute a 10 ppm solution to 1 ppm, you would mix 1 part of the 10 ppm solution with 9 parts of a diluent (such as water). This would result in a 1 ppm concentration because the concentration has been decreased by a factor of 10 during the dilution process.
To prepare a 10 ppm dilution from a 100 ppm stock solution, you can use the dilution equation: C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock needed, C2 is the desired concentration, and V2 is the final volume. Here, C1 is 100 ppm, C2 is 10 ppm, and V2 is 25 ml. Rearranging the equation to solve for V1 gives you V1 = (C2 * V2) / C1 = (10 ppm * 25 ml) / 100 ppm = 2.5 ml. Therefore, you need to take 2.5 ml of the 100 ppm solution and dilute it with 22.5 ml of solvent (water or another appropriate diluent) to achieve a total volume of 25 ml at 10 ppm.
1000 ppm is equivalent to 1 milligram per milliliter.
Even a single drop of water will dilute 28 ppm of cyanide. Not by much, perhaps, but the question does not specify dilution to what degree.
To prepare a 0.2 ppm solution from a 1000 ppm solution, you would need to dilute the 1000 ppm solution by adding 5000 parts of solvent for every 1 part of the 1000 ppm solution. This means mixing 1 part of the 1000 ppm solution with 5000 parts of solvent to achieve a 0.2 ppm concentration.
To dilute a 10 ppm solution to 1 ppm, you would mix 1 part of the 10 ppm solution with 9 parts of a diluent (such as water). This would result in a 1 ppm concentration because the concentration has been decreased by a factor of 10 during the dilution process.
Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.
if ppm means part per million, 1000 ppm = 1000 p 1000000 = 1 p 1000 = 0.1%
1000 ppm is equivalent to 1 milligram per milliliter.
Preparation of PPM level standards of ethanol in waterUse the absolute alcohol to prepare the stock solutions of known concentration say for example: 100 ml of 1 g/L of ethanol solution1 g/L is equal to 1000 mg/L which is 1000 ppm. Otherwise the concentration of the 100 ml stock solution is 1000 ppm.Next step: Perform serial dilution procedure to prepare the required ppm level of ethanol standards. For performing the serial dilution, u have to convert the weight of ethanol into volume by dividing the weight by density of ethanol. Density of ethanol = 789 kg/cu.m or 789 g/L.
no
500 ppm.
Chlorine concentration at 500 ppm hazards to health to wash dishes in
*1000
Yes.
Even a single drop of water will dilute 28 ppm of cyanide. Not by much, perhaps, but the question does not specify dilution to what degree.