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What is the final temperature of a gas if three moles of an ideal monatomic gas are at a temperature of 335 K Then 2893 J of heat is added to the gas and 811 J of work is done on it?
Wiki User
∙ 14y ago
dude im not gonna do your homework for you.
Wiki User
∙ 14y ago
Using the first law of thermodynamics, we have: ΔU = Q - W. Substituting the values, we get ΔU = 2893 J - 811 J = 2082 J. For a monatomic ideal gas, ΔU = (3/2)nRΔT, where n is the number of moles, R is the ideal gas constant, and ΔT is the change in temperature. Solving for ΔT, we find ΔT = ΔU / ((3/2)nR). Substituting the values gives ΔT = 2082 J / ((3/2) * 3 * 8.314 J/mol⋅K) = 34.5 K. Therefore, the final temperature is 335 K + 34.5 K = 369.5 K.
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