The total mass of the solution is the sum of the mass of the solute (glucose) and the mass of the solvent (water), which is 50 g + 1000 g = 1050 g. The mass percent of the solute (glucose) in the solution is the mass of the solute divided by the total mass of the solution, multiplied by 100. Therefore, the mass percent of glucose in the solution is (50 g / 1050 g) x 100 = 4.76%.
Mass percent is the ratio of the mass of solute to the total mass of solution expressed as a percent Here we have 4.0 g solute and total mass of solution of 4.0 g + 50.0 g = 54.0 g. So, the mass percent of KCl = 4.0 g/54.0g (x100) = 7.41% (3 sig figs)
The number of moles is mass in g/molar mass in g.
To find the mass in grams of 0.330 mol of calcium, you need to use the molar mass of calcium which is 40.08 g/mol. Mass = moles x molar mass Mass = 0.330 mol x 40.08 g/mol = 13.24 g.
Example:- 454 g of orange jam contain 83 g sugar454 g jam---------------83 g sugar100 g jam----------------x g sugarx= 100x83/454= 18,18 g sugar (or 18 % sugar)
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
The answer is 18432
18432
The initial mass is 48,702 g.
% by mass is the mass of the solute divide by the total mass of solution times 100%. Or put another way, % by mass = mass solute/total mass of soln (x100%).Mass solute = 4.35 gMass of solution = 4.35 g + 105 g = 109.35 g (assuming a density of 1g/ml for water)% NaCl by mass = 4.35 g/109.35 g (x100%) = 3.98 % (to 3 significant figures)
the rapster (ME) , dinosaur585 , dj 18432 (my friends)
The total mass of the solution is the sum of the mass of the solute (glucose) and the mass of the solvent (water), which is 50 g + 1000 g = 1050 g. The mass percent of the solute (glucose) in the solution is the mass of the solute divided by the total mass of the solution, multiplied by 100. Therefore, the mass percent of glucose in the solution is (50 g / 1050 g) x 100 = 4.76%.
32 g
The error in the measurement was 7.5 g. This was calculated by subtracting the estimated mass (35 g) from the actual mass (42.5 g).
The mass percent of sodium chloride can be calculated as follows: Mass of NaCl = 1 g Mass of water = 50 g Total mass of solution = 1 g + 50 g = 51 g Mass percent of NaCl = (Mass of NaCl / Total mass of solution) x 100% = (1 g / 51 g) x 100% ≈ 1.96%
This mass is 2,469 g.
To find the mass of oxygen in sulfuric acid (H2SO4), we first need to calculate the molar mass of the compound. The molar mass of H2SO4 is 98.08 g/mol. The molar mass of oxygen in H2SO4 is 4 * 16 = 64 g/mol. To find the mass of oxygen in 250 g of H2SO4, we can use the proportion: (64 g / 98.08 g) * 250 g = 161.3 g of oxygen.